#include <iostream>
class base
{
public:
virtual void print (int a)
{
std::cout << "a: " << a << " base\n";
}
virtual void print (int a, int b)
{
std::cout << "base\n";
}
};
class derived : public base
{
public:
virtual void print (double d)
{
std::cout << "derived\n";
}
};
int main ()
{
int i = 10;
double d = 10000.0;
base *b = new derived ();
b->print (i, i);
b->print (d);
return 0;
}
这个函数的输出是:
base
a: 10000 base
- 为什么
b->print (d)
不会调用派生类的实现,而是对'd'
进行静态转换以与基类实现匹配? - 在虚函数查找期间应用了哪个规则?