Android: 窗口管理器: Android视图窗口泄漏

Question

我刚解决了第一个问题，现在又出现了这个:( 请帮我修复它...

03-02 12:47:02.785 9439-9439/com.ucu.ccs.classrecord E/WindowManager﹕ android.view.WindowLeaked: Activity com.ucu.ccs.classrecord.Login has leaked window com.android.internal.policy.impl.PhoneWindow$DecorView{6d17cc4 V.E..... R......D 0,0-1002,348} that was originally added here at android.view.ViewRootImpl.(ViewRootImpl.java:465) at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:277) at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:69) at android.app.Dialog.show(Dialog.java:312) at com.ucu.ccs.classrecord.Login$AttemptLogin.onPreExecute(Login.java:158) at android.os.AsyncTask.executeOnExecutor(AsyncTask.java:587) at android.os.AsyncTask.execute(AsyncTask.java:535) at com.ucu.ccs.classrecord.Login.isOnline(Login.java:113) at com.ucu.ccs.classrecord.Login$1.onClick(Login.java:73) at android.view.View.performClick(View.java:5197) at android.view.View$PerformClick.run(View.java:20926) at android.os.Handler.handleCallback(Handler.java:739) at android.os.Handler.dispatchMessage(Handler.java:95) at android.os.Looper.loop(Looper.java:145) at android.app.ActivityThread.main(ActivityThread.java:5942) at java.lang.reflect.Method.invoke(Native Method) at java.lang.reflect.Method.invoke(Method.java:372) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1399) at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1194)

这是我的代码:

buttonLogin.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                String instructor_id = editUser.getText().toString().trim();
                String password = editPass.getText().toString().trim();

                SharedPreferences preferences = getSharedPreferences("MyApp", MODE_PRIVATE);
                preferences.edit().putString("password", password).commit();
                preferences.edit().putString("inst_id", instructor_id).commit();

                if (editUser.getText().toString().equals("") || editPass.getText().toString().equals("")){
                    Toast.makeText(getApplicationContext(),"Please enter Instructor ID and Password", Toast.LENGTH_LONG).show();
                }else {
                    isOnline();
                }

            }
        });

public boolean isOnline(){
        ConnectivityManager connectivityManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
        NetworkInfo networkInfo = connectivityManager.getActiveNetworkInfo();
        if (networkInfo != null && networkInfo.isConnectedOrConnecting()){
            new AttemptLogin().execute();
        }else {
            checkInternet();
        }
        return false;
    }

class AttemptLogin extends AsyncTask<String, String, String> {
        boolean failure = false;
        String inst_id = editUser.getText().toString();
        String password = editPass.getText().toString();

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            pDialog = new ProgressDialog(Login.this);
            pDialog.setMessage("Attempting login...");
            pDialog.setIndeterminate(false);
            pDialog.setCancelable(true);
            pDialog.show();
        }

        @Override
        protected String doInBackground(String... params) {
            int success;
            try{
                List<NameValuePair> mList = new ArrayList<NameValuePair>();
                mList.add(new BasicNameValuePair("instructor_id", inst_id));
                mList.add(new BasicNameValuePair("password", password));

                Log.d("request!", "starting");

                JSONObject json = jsonParser.makeHttpRequest(LOGIN_URL, "POST", mList);
                Log.d("Login attempt", json.toString());

                success = json.getInt(TAG_SUCCESS);
                if (success == 1) {
                    Log.d("Login Successful!", json.toString());
                    Intent i = new Intent(Login.this, MainActivity.class);
                    startActivity(i);
                    //finish();
                    return json.getString(TAG_MESSAGE);
                }else{
                    Log.d("Login Failure!", json.getString(TAG_MESSAGE));
                    return json.getString(TAG_MESSAGE);
                }

            }catch (JSONException e){
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            session.setLogin(true);
            pDialog.dismiss();
            if (s != null){
                Toast.makeText(getApplicationContext(), s, Toast.LENGTH_SHORT).show();
            }
        }
    }

- user3660378

---

你做了什么？我的意思是在点击按钮后你做了什么？ - sanky jain

我只是点击了按钮，然后进度对话框出现了，在处理完成后应用程序崩溃了。 - user3660378

看起来你的对话框仍在显示，请查看此链接：https://dev59.com/8HLYa4cB1Zd3GeqPZZTT#16768747 - Manu

你为什么关心这个警告？它导致你的应用程序崩溃了吗？ - IgorGanapolsky

Answer 1

在退出一个Activity后，你正在尝试展示一个对话框。 在你的doInBackground中，在你切换Activity之前dismiss对话框startActivity(i) 尝试这样做并让我知道是否有效。

- Rakshit Nawani

Answer 2

实际上，你的活动正在以某种方式结束，所以你需要关闭对话框。

在onPause()方法中添加以下代码。

if(isFinishing()){
    if (pDialog!= null) {
        pDialog.dismiss();
        pDialog= null;
    }
}

- sanky jain