值得考虑你想要的JSON。
假设你有这个类
class Person
{
public string Name { get; set; }
public PhoneNumber HomePhone { get; set; }
}
你想将它序列化为JSON格式,像这样
{ "Name":"Joe", "HomePhone": "555-555-555" }
但是你会得到JSON,类似这样的内容
{ "Name":"Joe","HomePhone": {"Number": "555-555-555"} }
--
为了理解这一点,考虑到
Person的属性
Number是一个
对象。JSON将期望至少有一个
{}来包装该对象 - 或者更准确地说,在{}内部有一组名称/值。
如果您真的非常想要前面的JSON语法,您需要为
Person对象注册自定义转换器,以便您可以说服它将其序列化和反序列化为字符串(请参见下面的代码示例)。
然而,我建议您接受因为PhoneNumber是一个对象,所以当序列化为JSON时,它对应于名称/值字典,并接受JSON看起来可能不太“干净”的事实。
以下是一个代码示例,可以实现您最初的目标(不推荐使用)。
class Person
{
public string Name { get; set; }
public PhoneNumber HomeNumber { get; set; }
}
struct PhoneNumber
{
private string _number;
public PhoneNumber(string number)
{
_number = number;
}
public override string ToString()
{
return _number;
}
}
class PersonConverter : JavaScriptConverter
{
public override IEnumerable<Type> SupportedTypes
{
get { yield return typeof(Person); }
}
public override IDictionary<string, object> Serialize(object obj, JavaScriptSerializer serializer)
{
Person person = obj as Person;
if (person != null)
{
Dictionary<string, object> dict = new Dictionary<string, object>();
dict["Name"] = person.Name;
dict["HomeNumber"] = person.HomeNumber.ToString();
return dict;
}
return new Dictionary<string, object>();
}
public override object Deserialize(IDictionary<string, object> dict, Type type, JavaScriptSerializer serializer)
{
if (dict == null)
throw new ArgumentNullException("dict");
if (type == typeof(Person))
{
string name = (string)dict["Name"];
string homeNumber = (string)dict["HomeNumber"];
Person person = new Person()
{
Name = name,
HomeNumber = new PhoneNumber(homeNumber)
};
return person;
}
return null;
}
}
class Program
{
static void Main(string[] args)
{
PhoneNumber number = new PhoneNumber("555 555");
Person joe = new Person() { Name = "Joe", HomeNumber = number };
JavaScriptSerializer serializer = new JavaScriptSerializer();
serializer.RegisterConverters(new JavaScriptConverter[] { new PersonConverter() });
Console.Out.WriteLine(serializer.Serialize(joe));
}
}