我有困难在多维数组中循环并删除特定元素数组。我的多维数组看起来像这样:
myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
如果我有数字29,那么最有效的方法是循环遍历这个数组并删除第二个元素为29的数组元素吗?即 ["Dick", "29"]
我有困难在多维数组中循环并删除特定元素数组。我的多维数组看起来像这样:
myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
如果我有数字29,那么最有效的方法是循环遍历这个数组并删除第二个元素为29的数组元素吗?即 ["Dick", "29"]
var myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
var myNewArray = myArray.filter(function(item){ return item[1] != 29 })
.filter使用本地代码循环遍历您的数组。构建一个新数组当然可能比仅从旧数组中切出一部分更昂贵,需要测试。
myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
for(var i = 0; i <= myArray.length - 1; i++){
if(myArray[i][1] == "29"){
myArray[i].splice(0,2);
}
}
console.log(myArray);
// returns [ [ 'Tom', '161' ], [], [ 'Harry', '46' ] ]
const organizers = [
{
id: '83f58b20-011d-11ed-b71c-47e6c5dfe098',
createdAt: '2022-07-11T13:29:39.794Z',
updatedAt: '2022-07-11T13:29:39.794Z',
organizerId: '83deced0-011d-11ed-b71c-47e6c5dfe098',
tournamentId: '83b37910-011d-11ed-b71c-47e6c5dfe098',
organizerName: null
},
{
id: '83f58b21-011d-11ed-b71c-47e6c5dfe098',
createdAt: '2022-07-11T13:29:39.794Z',
updatedAt: '2022-07-11T13:29:39.794Z',
organizerId: '83e18df0-011d-11ed-b71c-47e6c5dfe098',
tournamentId: '83b37910-011d-11ed-b71c-47e6c5dfe098',
organizerName: 'MANOJ ABCD'
}
];
const removeorganizerId = "83e18df0-011d-11ed-b71c-47e6c5dfe098"
var myNewArray = organizers.filter(function(item){ return item.organizerId !== removeorganizerId });
console.log("myNewArray ===> ", myNewArray);
查看演示请点击这里
brbcoding的答案删除了数组元素的内容,但并没有将其删除。以下是一个解决方法:
myArray = [["Tom", "161"], ["Dick", "29"], ["Harry", "46"]];
document.getElementById("a").innerHTML = myArray;
for(var i = 0; i <= myArray.length - 1; i++){
if(myArray[i][1] == "29"){
myArray.splice(i--,1);
}
}
document.getElementById("b").innerHTML = myArray;
console.log(myArray);
https://jsfiddle.net/tmzshopping/dfdveazk/
splice函数可以删除数组中的一行(在参数中指定为1),如果将1替换为2,则可以删除两行。i--会减少数组的长度。
array_name = [[1,2,3],[],['Hi','hello','world']]
let temp = []
array_name.forEach(element => {
if (element != '' || `enter condition here`) {
temp.push(element)
}
});
array_name = temp; // array_name = [ [1,2,3], ['Hi','hello','world'] ]
for
循环。根据您对数据的其他操作,您可以首先对数组进行排序。 - Felix KlingindexOf
不会真正起作用,因为你正在寻找元素内的元素。但是你可以通过 http://jsperf.com/ 轻松测试哪个更快。 - Felix Kling