国家名称转换为ISO 3166-2代码

Question

我知道如何通过使用RegionInfo将ISO 3166-2代码转换为完整的英文名称，例如“US”转换为“United States”。

但是，如何进行相反的操作，即将“United States”转换为“US”？

- jacobz

---

很高兴看到有人愿意提供帮助，但是得到基本上相同的答案四次有点不必要。圣诞快乐！ - Onots

Answer 1

//Get the cultureinfo
RegionInfo rInfo = new RegionInfo("us");
string s = rInfo.EnglishName;

//Convert it back
CultureInfo[] cultures = CultureInfo.GetCultures(CultureTypes.SpecificCultures);
 CultureInfo cInfo = cultures.FirstOrDefault(culture => new RegionInfo(culture.LCID).EnglishName == s);

- Mitja

Answer 2

主要思路：获取所有区域对象，从中选择包含给定全名的一个对象。

var regionFullNames = CultureInfo
                      .GetCultures( CultureTypes.SpecificCultures )
                      .Select( x => new RegionInfo(x.LCID) )
                      ;
var twoLetterName = regionFullNames.FirstOrDefault(
                       region => region.EnglishName.Contains("United States")
                    );

- yesenin

Answer 3

您可以像这样做：

class CountryCodeMap
{
  private static Dictionary<string,string> map =
    CultureInfo
    .GetCultures(CultureTypes.AllCultures)
    .Where( ci => ci.ThreeLetterISOLanguageName != "ivl" )
    .Where( ci => !ci.IsNeutralCulture )
    .Select( ci => new RegionInfo(ci.LCID) )
    .Distinct()
    .ToDictionary( r => r.Name , r => r.EnglishName )
    ;

  public static string GetCountryName( string isoCountryCode )
  {
    string countryName ;
    bool found = map.TryGetValue( isoCountryCode, out countryName ) ;

    if ( !found ) throw new ArgumentOutOfRangeException("isoCountryCode") ;

    return countryName ;
  }

}

- Nicholas Carey

Answer 4

        /// <summary>
        /// English Name for country
        /// </summary>
        /// <param name="countryEnglishName"></param>
        /// <returns>
        /// Returns: RegionInfo object for successful find.
        /// Returns: Null if object is not found.
        /// </returns>
        static RegionInfo getRegionInfo (string countryEnglishName)
        {
            //Note: This is computed every time. This may be optimized
            var regionInfos = CultureInfo.GetCultures(CultureTypes.SpecificCultures)
               .Select(c => new RegionInfo(c.LCID))
               .Distinct()
               .ToList();
             RegionInfo r = regionInfos.Find(
                    region => region.EnglishName.ToLower().Equals(countryEnglishName.ToLower()));                       
             return r;
        }

- Vikrant