在我的Json解析中,我从这个json中获取了url。我需要将该Url链接显示在Webview中。我应该怎么做?
代码 在这里:
TextView tv = (TextView)findViewById(R.id.textView1);
Bundle bundle = new Bundle();
bundle = getIntent().getExtras();
String id = bundle .getString("id");
String firstName = bundle.getString("firstName");
String lastName = bundle.getString("lastName");
String headline = bundle.getString("headline");
String pictureUrl = bundle.getString("pictureUrl");
String url = bundle.getString("url");
Log.v("LV","id :"+id+"\n"+"firstname :"+firstName+"\n"+"lastname :"+lastName+"\n"+"headline :"+headline+"\n"+"pictureUrl :"+pictureUrl+"\n"+"siteStandardProfileRequest"+url);
tv.setText("id :"+id+"\n"+"firstname :"+firstName+"\n"+"lastname :"+lastName+"\n"+"headline :"+headline+"\n"+"pictureUrl :"+pictureUrl+"\n"+"Profile URL :"+url);