我希望以以下方式在字典中存储单词:
通过单词获取单词代码: dict["SomeWord"]
-> 123
,通过单词代码获取单词: dict[123]
-> "SomeWord"
这可行吗?当然,一种实现方式是使用两个字典:Dictionary<string,int>
和 Dictionary<int,string>
,但是否存在其他的方式?
我希望以以下方式在字典中存储单词:
通过单词获取单词代码: dict["SomeWord"]
-> 123
,通过单词代码获取单词: dict[123]
-> "SomeWord"
这可行吗?当然,一种实现方式是使用两个字典:Dictionary<string,int>
和 Dictionary<int,string>
,但是否存在其他的方式?
我写了几个快速类,可以让你做想要的事情。你可能需要通过添加更多功能来扩展它,但这是一个很好的起点。
代码的使用方式如下:
var map = new Map<int, string>();
map.Add(42, "Hello");
Console.WriteLine(map.Forward[42]);
// Outputs "Hello"
Console.WriteLine(map.Reverse["Hello"]);
//Outputs 42
以下是定义:
public class Map<T1, T2>
{
private Dictionary<T1, T2> _forward = new Dictionary<T1, T2>();
private Dictionary<T2, T1> _reverse = new Dictionary<T2, T1>();
public Map()
{
this.Forward = new Indexer<T1, T2>(_forward);
this.Reverse = new Indexer<T2, T1>(_reverse);
}
public class Indexer<T3, T4>
{
private Dictionary<T3, T4> _dictionary;
public Indexer(Dictionary<T3, T4> dictionary)
{
_dictionary = dictionary;
}
public T4 this[T3 index]
{
get { return _dictionary[index]; }
set { _dictionary[index] = value; }
}
}
public void Add(T1 t1, T2 t2)
{
_forward.Add(t1, t2);
_reverse.Add(t2, t1);
}
public Indexer<T1, T2> Forward { get; private set; }
public Indexer<T2, T1> Reverse { get; private set; }
}
_forward.Add
可能成功,但 _reverse.Add
可能失败,导致你只添加了一半的键值对。 - user743382Forward
字典属性本身(该属性有private set;
),而是通过Indexer类的索引器属性来修改该字典中的值,进而将其传递给字典。public T4 this[T3 index] { get { return _dictionary[index]; } set { _dictionary[index] = value; } }
这样就破坏了正向/反向查找。 - Jeroen van Langen遗憾的是,你需要两个字典,一个用于每个方向。不过,你可以使用LINQ轻松获取反向字典:
很抱歉,您需要两个字典,一个用于正向,另一个用于反向。不过,您可以使用LINQ轻松地获取反向字典:
Dictionary<T1, T2> dict = new Dictionary<T1, T2>();
Dictionary<T2, T1> dictInverse = dict.ToDictionary((i) => i.Value, (i) => i.Key);
在Enigmativity代码的基础上进行了扩展,添加了初始化和Contains方法。
public class Map<T1, T2> : IEnumerable<KeyValuePair<T1, T2>>
{
private readonly Dictionary<T1, T2> _forward = new Dictionary<T1, T2>();
private readonly Dictionary<T2, T1> _reverse = new Dictionary<T2, T1>();
public Map()
{
Forward = new Indexer<T1, T2>(_forward);
Reverse = new Indexer<T2, T1>(_reverse);
}
public Indexer<T1, T2> Forward { get; private set; }
public Indexer<T2, T1> Reverse { get; private set; }
public void Add(T1 t1, T2 t2)
{
_forward.Add(t1, t2);
_reverse.Add(t2, t1);
}
public void Remove(T1 t1)
{
T2 revKey = Forward[t1];
_forward.Remove(t1);
_reverse.Remove(revKey);
}
public void Remove(T2 t2)
{
T1 forwardKey = Reverse[t2];
_reverse.Remove(t2);
_forward.Remove(forwardKey);
}
IEnumerator IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
public IEnumerator<KeyValuePair<T1, T2>> GetEnumerator()
{
return _forward.GetEnumerator();
}
public class Indexer<T3, T4>
{
private readonly Dictionary<T3, T4> _dictionary;
public Indexer(Dictionary<T3, T4> dictionary)
{
_dictionary = dictionary;
}
public T4 this[T3 index]
{
get { return _dictionary[index]; }
set { _dictionary[index] = value; }
}
public bool Contains(T3 key)
{
return _dictionary.ContainsKey(key);
}
}
}
这里有一个使用案例,检查有效的括号
public static class ValidParenthesisExt
{
private static readonly Map<char, char>
_parenthesis = new Map<char, char>
{
{'(', ')'},
{'{', '}'},
{'[', ']'}
};
public static bool IsValidParenthesis(this string input)
{
var stack = new Stack<char>();
foreach (var c in input)
{
if (_parenthesis.Forward.Contains(c))
stack.Push(c);
else
{
if (stack.Count == 0) return false;
if (_parenthesis.Reverse[c] != stack.Pop())
return false;
}
}
return stack.Count == 0;
}
}
{
get { return _dictionary[index]; }
set { _dictionary[index] = value; }
}```
由于这段代码,字典可以指向键值对之外的值。
- Aditya Nadigvar parent = parentMap.Reverse[pair.Key];
parentMap.Forward[parent] = <某个值>;
- Aditya NadigTKey
和 TValue
都是相同类型(并且它们的运行时值域已知为不相交),则您只需为每个键/值配对创建两个条目,就可以使用同一个字典:
dict["SomeWord"]= "123"
和 dict["123"]="SomeWord"
这样一来,单个字典就可以用于任何类型的查找。
算了,我也来加入这个讨论:
public class BijectiveDictionary<TKey, TValue>
{
private EqualityComparer<TKey> _keyComparer;
private Dictionary<TKey, ISet<TValue>> _forwardLookup;
private EqualityComparer<TValue> _valueComparer;
private Dictionary<TValue, ISet<TKey>> _reverseLookup;
public BijectiveDictionary()
: this(EqualityComparer<TKey>.Default, EqualityComparer<TValue>.Default)
{
}
public BijectiveDictionary(EqualityComparer<TKey> keyComparer, EqualityComparer<TValue> valueComparer)
: this(0, EqualityComparer<TKey>.Default, EqualityComparer<TValue>.Default)
{
}
public BijectiveDictionary(int capacity, EqualityComparer<TKey> keyComparer, EqualityComparer<TValue> valueComparer)
{
_keyComparer = keyComparer;
_forwardLookup = new Dictionary<TKey, ISet<TValue>>(capacity, keyComparer);
_valueComparer = valueComparer;
_reverseLookup = new Dictionary<TValue, ISet<TKey>>(capacity, valueComparer);
}
public void Add(TKey key, TValue value)
{
AddForward(key, value);
AddReverse(key, value);
}
public void AddForward(TKey key, TValue value)
{
ISet<TValue> values;
if (!_forwardLookup.TryGetValue(key, out values))
{
values = new HashSet<TValue>(_valueComparer);
_forwardLookup.Add(key, values);
}
values.Add(value);
}
public void AddReverse(TKey key, TValue value)
{
ISet<TKey> keys;
if (!_reverseLookup.TryGetValue(value, out keys))
{
keys = new HashSet<TKey>(_keyComparer);
_reverseLookup.Add(value, keys);
}
keys.Add(key);
}
public bool TryGetReverse(TValue value, out ISet<TKey> keys)
{
return _reverseLookup.TryGetValue(value, out keys);
}
public ISet<TKey> GetReverse(TValue value)
{
ISet<TKey> keys;
TryGetReverse(value, out keys);
return keys;
}
public bool ContainsForward(TKey key)
{
return _forwardLookup.ContainsKey(key);
}
public bool TryGetForward(TKey key, out ISet<TValue> values)
{
return _forwardLookup.TryGetValue(key, out values);
}
public ISet<TValue> GetForward(TKey key)
{
ISet<TValue> values;
TryGetForward(key, out values);
return values;
}
public bool ContainsReverse(TValue value)
{
return _reverseLookup.ContainsKey(value);
}
public void Clear()
{
_forwardLookup.Clear();
_reverseLookup.Clear();
}
}
在其中添加一些数据:
var lookup = new BijectiveDictionary<int, int>();
lookup.Add(1, 2);
lookup.Add(1, 3);
lookup.Add(1, 4);
lookup.Add(1, 5);
lookup.Add(6, 2);
lookup.Add(6, 8);
lookup.Add(6, 9);
lookup.Add(6, 10);
然后进行查找:
lookup[2] --> 1, 6
lookup[3] --> 1
lookup[8] --> 6
我将Enigmativity的答案扩展并制作为一个nuget包https://www.nuget.org/packages/BidirectionalMap/
该项目是开源的,源代码可以在这里找到。
您可以使用这个扩展方法,虽然它使用枚举,因此对于大数据集可能不太高效。如果您担心效率问题,则需要两个字典。如果您想将这两个字典封装到一个类中,请参见这个问题的已接受答案:C#中的双向1对1字典
public static class IDictionaryExtensions
{
public static TKey FindKeyByValue<TKey, TValue>(this IDictionary<TKey, TValue> dictionary, TValue value)
{
if (dictionary == null)
throw new ArgumentNullException("dictionary");
foreach (KeyValuePair<TKey, TValue> pair in dictionary)
if (value.Equals(pair.Value)) return pair.Key;
throw new Exception("the value is not found in the dictionary");
}
}
new Map <int, string>(new Dictionary<int, string> { ... });
. 有点丑,但只有一点 (; - Sebastian Werk这是Xavier John答案的修改版,增加了一个额外的构造函数来接受前向和后向比较器。例如,这将支持不区分大小写的键。如果需要,可以添加更多的构造函数来将其他参数传递给前向和后向字典构造函数。
public class Map<T1, T2> : IEnumerable<KeyValuePair<T1, T2>>
{
private readonly Dictionary<T1, T2> _forward;
private readonly Dictionary<T2, T1> _reverse;
/// <summary>
/// Constructor that uses the default comparers for the keys in each direction.
/// </summary>
public Map()
: this(null, null)
{
}
/// <summary>
/// Constructor that defines the comparers to use when comparing keys in each direction.
/// </summary>
/// <param name="t1Comparer">Comparer for the keys of type T1.</param>
/// <param name="t2Comparer">Comparer for the keys of type T2.</param>
/// <remarks>Pass null to use the default comparer.</remarks>
public Map(IEqualityComparer<T1> t1Comparer, IEqualityComparer<T2> t2Comparer)
{
_forward = new Dictionary<T1, T2>(t1Comparer);
_reverse = new Dictionary<T2, T1>(t2Comparer);
Forward = new Indexer<T1, T2>(_forward);
Reverse = new Indexer<T2, T1>(_reverse);
}
// Remainder is the same as Xavier John's answer:
// https://dev59.com/t2gu5IYBdhLWcg3w8Lav#41907561
...
}
一个不区分大小写的键的使用示例:
Map<int, string> categories =
new Map<int, string>(null, StringComparer.CurrentCultureIgnoreCase)
{
{ 1, "Bedroom Furniture" },
{ 2, "Dining Furniture" },
{ 3, "Outdoor Furniture" },
{ 4, "Kitchen Appliances" }
};
int categoryId = 3;
Console.WriteLine("Description for category ID {0}: '{1}'",
categoryId, categories.Forward[categoryId]);
string categoryDescription = "DINING FURNITURE";
Console.WriteLine("Category ID for description '{0}': {1}",
categoryDescription, categories.Reverse[categoryDescription]);
categoryDescription = "outdoor furniture";
Console.WriteLine("Category ID for description '{0}': {1}",
categoryDescription, categories.Reverse[categoryDescription]);
// Results:
/*
Description for category ID 3: 'Outdoor Furniture'
Category ID for description 'DINING FURNITURE': 2
Category ID for description 'outdoor furniture': 3
*/
这是我的代码。除了种子构造函数之外,一切都是O(1)。
using System.Collections.Generic;
using System.Linq;
public class TwoWayDictionary<T1, T2>
{
Dictionary<T1, T2> _Forwards = new Dictionary<T1, T2>();
Dictionary<T2, T1> _Backwards = new Dictionary<T2, T1>();
public IReadOnlyDictionary<T1, T2> Forwards => _Forwards;
public IReadOnlyDictionary<T2, T1> Backwards => _Backwards;
public IEnumerable<T1> Set1 => Forwards.Keys;
public IEnumerable<T2> Set2 => Backwards.Keys;
public TwoWayDictionary()
{
_Forwards = new Dictionary<T1, T2>();
_Backwards = new Dictionary<T2, T1>();
}
public TwoWayDictionary(int capacity)
{
_Forwards = new Dictionary<T1, T2>(capacity);
_Backwards = new Dictionary<T2, T1>(capacity);
}
public TwoWayDictionary(Dictionary<T1, T2> initial)
{
_Forwards = initial;
_Backwards = initial.ToDictionary(kvp => kvp.Value, kvp => kvp.Key);
}
public TwoWayDictionary(Dictionary<T2, T1> initial)
{
_Backwards = initial;
_Forwards = initial.ToDictionary(kvp => kvp.Value, kvp => kvp.Key);
}
public T1 this[T2 index]
{
get => _Backwards[index];
set
{
if (_Backwards.TryGetValue(index, out var removeThis))
_Forwards.Remove(removeThis);
_Backwards[index] = value;
_Forwards[value] = index;
}
}
public T2 this[T1 index]
{
get => _Forwards[index];
set
{
if (_Forwards.TryGetValue(index, out var removeThis))
_Backwards.Remove(removeThis);
_Forwards[index] = value;
_Backwards[value] = index;
}
}
public int Count => _Forwards.Count;
public bool Contains(T1 item) => _Forwards.ContainsKey(item);
public bool Contains(T2 item) => _Backwards.ContainsKey(item);
public bool Remove(T1 item)
{
if (!this.Contains(item))
return false;
var t2 = _Forwards[item];
_Backwards.Remove(t2);
_Forwards.Remove(item);
return true;
}
public bool Remove(T2 item)
{
if (!this.Contains(item))
return false;
var t1 = _Backwards[item];
_Forwards.Remove(t1);
_Backwards.Remove(item);
return true;
}
public void Clear()
{
_Forwards.Clear();
_Backwards.Clear();
}
}
error CS0121: The call is ambiguous between the following methods or properties: 'TwoWayDictionary<T1, T2>.TwoWayDictionary(Dictionary<T1, T2>)' and 'TwoWayDictionary<T1, T2>.TwoWayDictionary(Dictionary<T2, T1>)'
- Graham这是一个老问题,但我想添加两个扩展方法,以防有人发现它有用。第二个不太有用,但如果需要支持一对一的字典,则它提供了一个起点。
public static Dictionary<VALUE,KEY> Inverse<KEY,VALUE>(this Dictionary<KEY,VALUE> dictionary)
{
if (dictionary==null || dictionary.Count == 0) { return null; }
var result = new Dictionary<VALUE, KEY>(dictionary.Count);
foreach(KeyValuePair<KEY,VALUE> entry in dictionary)
{
result.Add(entry.Value, entry.Key);
}
return result;
}
public static Dictionary<VALUE, KEY> SafeInverse<KEY, VALUE>(this Dictionary<KEY, VALUE> dictionary)
{
if (dictionary == null || dictionary.Count == 0) { return null; }
var result = new Dictionary<VALUE, KEY>(dictionary.Count);
foreach (KeyValuePair<KEY, VALUE> entry in dictionary)
{
if (result.ContainsKey(entry.Value)) { continue; }
result.Add(entry.Value, entry.Key);
}
return result;
}