Spark 2.0.0:如何使用自定义编码类型聚合DataSet?

3

我有一些数据存储在DataSet[(Long, LineString)]中,使用元组编码器和kryo编码器对LineString进行编码。

implicit def single[A](implicit c: ClassTag[A]): Encoder[A] = Encoders.kryo[A](c)
implicit def tuple2[A1, A2](implicit
                            e1: Encoder[A1],
                            e2: Encoder[A2]
                           ): Encoder[(A1,A2)] = Encoders.tuple[A1,A2](e1, e2)
implicit val lineStringEncoder = Encoders.kryo[LineString]

val ds = segmentPoints.map(
  sp => {
    val p1 = new Coordinate(sp.lon_ini, sp.lat_ini)
    val p2 = new Coordinate(sp.lon_fin, sp.lat_fin)
    val coords = Array(p1, p2)

    (sp.id, gf.createLineString(coords))
  })
  .toDF("id", "segment")
  .as[(Long, LineString)]
  .cache

ds.show

    +----+--------------------+
    | id |       segment      |
    +----+--------------------+
    | 347|[01 00 63 6F 6D 2...|
    | 347|[01 00 63 6F 6D 2...|
    | 347|[01 00 63 6F 6D 2...|
    | 808|[01 00 63 6F 6D 2...|
    | 808|[01 00 63 6F 6D 2...|
    | 808|[01 00 63 6F 6D 2...|
    +----+--------------------+

我可以在段列上应用任何地图操作,并使用底层的LineString方法。
ds.map(_._2.getClass.getName).show(false)

+--------------------------------------+
|value                                 |
+--------------------------------------+
|com.vividsolutions.jts.geom.LineString|
|com.vividsolutions.jts.geom.LineString|
|com.vividsolutions.jts.geom.LineString|

我可以帮你进行翻译。以下是您需要翻译的内容:

我希望能创建一些UDAFs来处理相同id的片段,但我尝试了以下两种不同的方法,都没有成功:

1)使用聚合器:

val length = new Aggregator[LineString, Double, Double] with Serializable {
  def zero: Double = 0                     // The initial value.
  def reduce(b: Double, a: LineString) = b + a.getLength    // Add an element to the running total
  def merge(b1: Double, b2: Double) = b1 + b2 // Merge intermediate values.
  def finish(b: Double) = b
  // Following lines are missing on the API doc example but necessary to get
  // the code compile
  override def bufferEncoder: Encoder[Double] = Encoders.scalaDouble
  override def outputEncoder: Encoder[Double] = Encoders.scalaDouble
}.toColumn

ds.groupBy("id")
  .agg(length(col("segment")).as("kms"))
  .show(false)

我在这里遇到了以下错误:

 Exception in thread "main" org.apache.spark.sql.AnalysisException: unresolved operator 'Aggregate [id#603L], [id#603L, anon$1(com.test.App$$anon$1@5bf1e07, None, input[0, double, true] AS value#715, cast(value#715 as double), input[0, double, true] AS value#714, DoubleType, DoubleType)['segment] AS kms#721];

2)使用UserDefinedAggregateFunction

class Length extends UserDefinedAggregateFunction {
  val e = Encoders.kryo[LineString]

  // This is the input fields for your aggregate function.
  override def inputSchema: StructType = StructType(
    StructField("segment", DataTypes.BinaryType) :: Nil
  )

  // This is the internal fields you keep for computing your aggregate.
  override def bufferSchema: StructType = StructType(
      StructField("length", DoubleType) :: Nil
  )

  // This is the output type of your aggregatation function.
  override def dataType: DataType = DoubleType

  override def deterministic: Boolean = true

  // This is the initial value for your buffer schema.
  override def initialize(buffer: MutableAggregationBuffer): Unit = {
    buffer(0) = 0.0
  }

  // This is how to update your buffer schema given an input.
  override def update(buffer : MutableAggregationBuffer, input : Row) : Unit = {
    // val l0 = input.getAs[LineString](0) // Can't cast to LineString (I guess because it is searialized using given encoder)
    val b = input.getAs[Array[Byte]](0) // This works fine
    val lse = e.asInstanceOf[ExpressionEncoder[LineString]]
    val ls = lse.fromRow(???) // it expects InternalRow  but input is a Row instance
    // I also tried casting b.asInstance[InternalRow] without success.
    buffer(0) = buffer.getAs[Double](0) + ls.getLength
  }

  // This is how to merge two objects with the bufferSchema type.
  override def merge(buffer1: MutableAggregationBuffer, buffer2: Row): Unit = {
    buffer1(0) = buffer1.getAs[Double](0) + buffer2.getAs[Double](0)
  }

  // This is where you output the final value, given the final value of your bufferSchema.
  override def evaluate(buffer: Row): Any = {
    buffer.getDouble(0)
  }
}

val length = new Length
rseg
  .groupBy("id")
  .agg(length(col("segment")).as("kms"))
  .show(false)

我做错了什么?我想使用聚合API而不是使用RDD groupBy API与自定义类型一起使用。我在Spark文档中搜索,但找不到解决这个问题的答案,似乎它目前处于早期阶段。

谢谢。

2个回答

0
根据这个答案,没有简单的方法来传递嵌套类型的自定义编码器,例如(Long,LineString)在您的情况下。
一个选择是定义一个case class LineStringWithID,它将扩展带有id:Long属性的LineString,并使用来自SQLImplicits的编码器。
附言:您能否将您的问题分解成更小的部分,每个主题一个?

0
也许有人也在寻找这个:当使用Kryo编码器时,您不能使用基于未定义类型SQL的API进行数据集操作。 您只能使用带类型的API,并且在分组方面,这意味着您需要使用自定义聚合器,而不是自定义用户定义的聚合函数。 我认为您的聚合器实现是可以的,但是您的分组应更改为使用带类型的groupByKey与您的自定义聚合器实例
ds.groupByKey(_._1)
  .agg(length)
  .show(false)

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