如何将类作为参数传递给我的函数
到目前为止,我已经尝试过:
$sc = new SampleClass();
SampleFunction($sc);
function SampleFunction(&$refClass)
{
echo $refClass->getValue();
}
这是一个我正在做的简单示例,实际上在这个样例函数内我需要执行复杂的过程。但我没有从样例函数中得到任何响应。我做错了什么?谢谢。
更新
char.php
class Charss {
var $name=0;
var $hp=500;
var $spd=10;
var $rtime=10;
var $dmg=10;
function __construct( $name, $hp, $spd, $rtime , $dmg) {
$this->name = $name;
$this->hp = $hp;
$this->spd = $spd;
$this->rtime = $rtime;
$this->dmg = $dmg;
}
function get_name() {
return $this->name;
}
function set_name($new_name) {
$this->name = $new_name;
}
function get_hp() {
return $this->hp;
}
function set_hp($new_hp) {
$this->hp = $new_hp;
}
function get_spd() {
return $this->spd;
}
function set_spd($new_spd) {
$this->spd = $new_spd;
}
function get_rtime() {
return $this->rtime;
}
function set_rtime($new_rtime) {
$this->rtime = $new_rtime;
}
function get_dmg() {
return $this->get_dmg;
}
function set_dmg($new_dmg) {
$this->dmg = $new_dmg;
}
}
myclass.php
require("char.php");
class Person {
function try_process()
{
$chr1 = new Charss("Player1",500,3,0,50);
$chr2 = new Charss("Player2",500,6,0,70);
while ($chr1->get_hp() > 0 && $chr2->get_hp() > 0)
{
$sth = min($chr1->get_rtime(), $chr2->get_rtime());
if ($chr1->get_rtime() == 0 && $chr2->get_rtime() > 0)
{
exit;
Fight($chr1,$chr2);
$chr1->set_rtime($chr1->get_spd());
}
elseif ($chr2->get_rtime() == 0 && $chr1->get_rtime() > 0)
{
Fight($chr2,$chr1);
$chr2->set_rtime($chr2->get_spd());
}
else
{
Fight($chr1,$chr2); #having trouble with this
$chr1->set_rtime($chr1->get_spd());
}
$chr1->set_rtime($chr1->get_rtime() - $sth);
$chr2->set_rtime($chr2->get_rtime() - $sth);
}
}
function Fight($atk,$def)
{
$def->set_hp($def->get_hp() - $atk->get_dmg());
echo $atk->get_name() . " attacked " . $def->get_name() . " for " . $atk->get_dmg() . " damage";
}
所以我在按钮点击时调用 try_process 函数。
Fight($atk,$def)
,而是需要以$this->Fight($atk,$def)
的形式调用它,因为它是类的成员。 - mkgrunderCharss::get_dmg()
中,您使用了$get_dmg
属性(而不是$dmg
),但该属性不存在。我已经编辑了代码以使用$this
和存在的属性,现在它可以正常运行了。 :) - mkgrunder