在安卓中,我如何使用HTTP从移动设备向服务器发送文件(数据)?
很简单,您可以使用Post请求并将文件以二进制形式(字节数组)提交。
String url = "http://yourserver";
File file = new File(Environment.getExternalStorageDirectory().getAbsolutePath(),
"yourfile");
try {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(url);
InputStreamEntity reqEntity = new InputStreamEntity(
new FileInputStream(file), -1);
reqEntity.setContentType("binary/octet-stream");
reqEntity.setChunked(true); // Send in multiple parts if needed
httppost.setEntity(reqEntity);
HttpResponse response = httpclient.execute(httppost);
//Do something with response...
} catch (Exception e) {
// show error
}
可以通过向服务器发送HTTP Post请求来完成此操作:
HttpClient http = AndroidHttpClient.newInstance("MyApp");
HttpPost method = new HttpPost("http://url-to-server");
method.setEntity(new FileEntity(new File("path-to-file"), "application/octet-stream"));
HttpResponse response = http.execute(method);
$_FILES['file']
的默认名称是什么?它只是 basename($_FILES['file']['tmp_name'])
吗? - Brandon最有效的方法是使用android-async-http
您可以使用此代码上传文件:
// gather your request parameters
File myFile = new File("/path/to/file.png");
RequestParams params = new RequestParams();
try {
params.put("profile_picture", myFile);
} catch(FileNotFoundException e) {}
// send request
AsyncHttpClient client = new AsyncHttpClient();
client.post(url, params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(int statusCode, Header[] headers, byte[] bytes) {
// handle success response
}
@Override
public void onFailure(int statusCode, Header[] headers, byte[] bytes, Throwable throwable) {
// handle failure response
}
});
请注意,您可以直接将此代码放入主活动中,无需显式创建后台任务。 AsyncHttp 将替您处理此操作!
将所有内容封装在异步任务中,以避免线程错误。
public class AsyncHttpPostTask extends AsyncTask<File, Void, String> {
private static final String TAG = AsyncHttpPostTask.class.getSimpleName();
private String server;
public AsyncHttpPostTask(final String server) {
this.server = server;
}
@Override
protected String doInBackground(File... params) {
Log.d(TAG, "doInBackground");
HttpClient http = AndroidHttpClient.newInstance("MyApp");
HttpPost method = new HttpPost(this.server);
method.setEntity(new FileEntity(params[0], "text/plain"));
try {
HttpResponse response = http.execute(method);
BufferedReader rd = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
final StringBuilder out = new StringBuilder();
String line;
try {
while ((line = rd.readLine()) != null) {
out.append(line);
}
} catch (Exception e) {}
// wr.close();
try {
rd.close();
} catch (IOException e) {
e.printStackTrace();
}
// final String serverResponse = slurp(is);
Log.d(TAG, "serverResponse: " + out.toString());
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
}
最有效的方法是使用org.apache.http.entity.mime.MultipartEntity;
可以从链接中查看这段代码,使用org.apache.http.entity.mime.MultipartEntity;
public class SimplePostRequestTest3 {
/**
* @param args
*/
public static void main(String[] args) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://localhost:8080/HTTP_TEST_APP/index.jsp");
try {
FileBody bin = new FileBody(new File("C:/ABC.txt"));
StringBody comment = new StringBody("BETHECODER HttpClient Tutorials");
MultipartEntity reqEntity = new MultipartEntity();
reqEntity.addPart("fileup0", bin);
reqEntity.addPart("fileup1", comment);
reqEntity.addPart("ONE", new StringBody("11111111"));
reqEntity.addPart("TWO", new StringBody("222222222"));
httppost.setEntity(reqEntity);
System.out.println("Requesting : " + httppost.getRequestLine());
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String responseBody = httpclient.execute(httppost, responseHandler);
System.out.println("responseBody : " + responseBody);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
httpclient.getConnectionManager().shutdown();
}
}
}