如何将混合维度的数组展平为二维列表?

3

我知道有很多关于如何将二维列表展平的帖子,但这个略有不同,因为它是二维和三维列表的混合:

items = [[255, 204, 204], ..., [255, 179, 179], [[250, 250, 250], ..., [220, 220, 220]]]

我希望这个列表只有两个维度:
items = [[255, 204, 204], ..., [255, 179, 179], [250, 250, 250], ..., [220, 220, 220]]

我尝试使用列表推导式,但是它不能正确地展开列表:
flat_list = [item for items in l for item in items]

什么是将混合维度数组转换为二维数组的最佳方法?
4个回答

5
old_list = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]                                                                                                         
new_list = []  
for i in old_list:
    if isinstance(i[0], list):
        for j in i:
            new_list.append(j)
    else:
        new_list.append(i)
print new_list

输出结果为:
[[255, 204, 204], [255, 179, 179], ['250, 250, 250'], ['220, 220, 220']]

3

您可以使用递归函数:

def flatten(items):
    for item in items:
        if isinstance(item[0], list):
            yield from flatten(item)
        else:
            yield item

示例:

>>> items = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]
>>> list(flatten(items))
[[255, 204, 204], [255, 179, 179], ['250, 250, 250'], ['220, 220, 220']]

1
from itertools import chain

items = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]

flat_list = list(chain.from_iterable(lst if isinstance(lst[0], list) else [lst] for lst in items))

print(flat_list)
>>> [[255, 204, 204], [255, 179, 179], ['250, 250, 250'], ['220, 220, 220']]

0
def tree2matrix(T):
  if T == []:
    return []
  elif type(T) is not list:
    return [[T]]
  elif type(T[0]) is not list:
    return [T]
  else:
    return tree2matrix(T[0]) + tree2matrix(T[1:])

X = [[255, 204, 204], [255, 179, 179], [['250, 250, 250'], ['220, 220, 220']]]
print(tree2matrix(X))

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