是否有任何JavaScript库可以像ASP.NET
一样将查询字符串转换成字典?
类似以下的用法:
var query = window.location.querystring["query"]?
在.NET领域之外,“查询字符串”是否被称为其他名称?为什么不将location.search
拆分为“键/值集合”?
编辑:我已经编写了自己的函数,但是否有任何主要的JavaScript库可以执行此操作?
是否有任何JavaScript库可以像ASP.NET
一样将查询字符串转换成字典?
类似以下的用法:
var query = window.location.querystring["query"]?
在.NET领域之外,“查询字符串”是否被称为其他名称?为什么不将location.search
拆分为“键/值集合”?
编辑:我已经编写了自己的函数,但是否有任何主要的JavaScript库可以执行此操作?
您可以从location.search属性中提取键/值对,该属性包含跟随?符号的URL的一部分,包括?符号。
function getQueryString() {
var result = {}, queryString = location.search.slice(1),
re = /([^&=]+)=([^&]*)/g, m;
while (m = re.exec(queryString)) {
result[decodeURIComponent(m[1])] = decodeURIComponent(m[2]);
}
return result;
}
// ...
var myParam = getQueryString()["myParam"];
dork.com/?equation=10=2
... - Christian C. Salvadó?val=foo&val=bar&val=baz
,你会如何适应这种情况? - Russ Bradberryval=foo&val=bar&val=baz
;它必须是 val[]=foo&val[]=bar&val[]=baz
。 - Brian Driscoll%20
结尾时,我觉得它不完整。因此,我用result[keyValuePair[0]] = decodeURIComponent((keyValuePair[1]+'').replace(/\+/g, '%20')) || '';
替换了result[keyValuePair[0]] = keyValuePair[1] || '';
。 - user24601var queryDict = {}
location.search.substr(1).split("&").forEach(function(item) {
queryDict[item.split("=")[0]] = item.split("=")[1]
})
对于查询字符串?a=1&b=2&c=3&d&e
,它返回:
> queryDict
a: "1"
b: "2"
c: "3"
d: undefined
e: undefined
请参考原始答案:如何在JavaScript中获取查询字符串的值?
"?a=1&b=2&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> queryDict
a: ["1", "5", "t e x t"]
b: ["2"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]
var queryDict = {}; location.search.substr(1).split("&").forEach( function(item) { queryDict[item.split("=")[0]] = item.split("=")[1]; } );
- QwertyObject.fromQueryString ( str , deep = true )
Converts the query string of a URL into an object. If deep is false, conversion will only accept shallow params (ie. no object or arrays with [] syntax) as these are not universally supported.
Object.fromQueryString('foo=bar&broken=wear') >{"foo":"bar","broken":"wear"} Object.fromQueryString('foo[]=1&foo[]=2') >{"foo":[1,2]}
例子:
var queryString = Object.fromQueryString(location.search);
var foo = queryString.foo;
/**
* @param qry the querystring
* @param name name of parameter
* @returns the parameter specified by name
* @author eduardo.medeirospereira@gmail.com
*/
function getQueryStringParameter(qry,name){
if(typeof qry !== undefined && qry !== ""){
var keyValueArray = qry.split("&");
for ( var i = 0; i < keyValueArray.length; i++) {
if(keyValueArray[i].indexOf(name)>-1){
return keyValueArray[i].split("=")[1];
}
}
}
return "";
}
Eldon McGuinness的这个Gist是我目前看到的最完整的JavaScript查询字符串解析器实现。
不幸的是,它是作为jQuery插件编写的。
我将它重写为纯JS,并进行了一些改进:
function parseQuery(str) {
var qso = {};
var qs = (str || document.location.search);
// Check for an empty querystring
if (qs == "") {
return qso;
}
// Normalize the querystring
qs = qs.replace(/(^\?)/, '').replace(/;/g, '&');
while (qs.indexOf("&&") != -1) {
qs = qs.replace(/&&/g, '&');
}
qs = qs.replace(/([\&]+$)/, '');
// Break the querystring into parts
qs = qs.split("&");
// Build the querystring object
for (var i = 0; i < qs.length; i++) {
var qi = qs[i].split("=");
qi = qi.map(function(n) {
return decodeURIComponent(n)
});
if (typeof qi[1] === "undefined") {
qi[1] = null;
}
if (typeof qso[qi[0]] !== "undefined") {
// If a key already exists then make this an object
if (typeof (qso[qi[0]]) == "string") {
var temp = qso[qi[0]];
if (qi[1] == "") {
qi[1] = null;
}
qso[qi[0]] = [];
qso[qi[0]].push(temp);
qso[qi[0]].push(qi[1]);
} else if (typeof (qso[qi[0]]) == "object") {
if (qi[1] == "") {
qi[1] = null;
}
qso[qi[0]].push(qi[1]);
}
} else {
// If no key exists just set it as a string
if (qi[1] == "") {
qi[1] = null;
}
qso[qi[0]] = qi[1];
}
}
return qso;
}
var results = parseQuery("?foo=bar&foo=boo&roo=bar;bee=bop;=ghost;=ghost2;&;checkbox%5B%5D=b1;checkbox%5B%5D=b2;dd=;http=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab&http=http%3A%2F%2Fw3schools2.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab");
{
"foo": ["bar", "boo" ],
"roo": "bar",
"bee": "bop",
"": ["ghost", "ghost2"],
"checkbox[]": ["b1", "b2"],
"dd": null,
"http": [
"http://w3schools.com/my test.asp?name=ståle&car=saab",
"http://w3schools2.com/my test.asp?name=ståle&car=saab"
]
}
另请参阅此Fiddle。
// How about this
function queryString(qs) {
var queryStr = qs.substr(1).split("&"),obj={};
for(var i=0; i < queryStr.length;i++)
obj[queryStr[i].split("=")[0]] = queryStr[i].split("=")[1];
return obj;
}
// Usage:
var result = queryString(location.search);
decodeURIComponent
。 - RupdecodeURIComponent
的评论还是适用的。 - Ruphttps://github.com/EldonMcGuinness/querystring.js
我本来想在他的帖子上发表评论,但是我没有足够的声望去这样做。:/下面的例子处理以下虽然不规则但是查询字符串:
?foo=bar&foo=boo&roo=bar;bee=bop;=ghost;=ghost2;&;checkbox%5B%5D=b1;checkbox%5B%5D=b2;dd=;http=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab&http=http%3A%2F%2Fw3schools2.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab
var qs = "?foo=bar&foo=boo&roo=bar;bee=bop;=ghost;=ghost2;&;checkbox%5B%5D=b1;checkbox%5B%5D=b2;dd=;http=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab&http=http%3A%2F%2Fw3schools2.com%2Fmy%20test.asp%3Fname%3Dst%C3%A5le%26car%3Dsaab";
//var qs = "?=&=";
//var qs = ""
var results = querystring(qs);
(document.getElementById("results")).innerHTML =JSON.stringify(results, null, 2);
<script
src="https://rawgit.com/EldonMcGuinness/querystring.js/master/dist/querystring.min.js"></script>
<pre id="results">RESULTS: Waiting...</pre>
function decode(s) {
try {
return decodeURIComponent(s).replace(/\r\n|\r|\n/g, "\r\n");
} catch (e) {
return "";
}
}
function getQueryString(win) {
var qs = win.location.search;
var multimap = {};
if (qs.length > 1) {
qs = qs.substr(1);
qs.replace(/([^=&]+)=([^&]*)/g, function(match, hfname, hfvalue) {
var name = decode(hfname);
var value = decode(hfvalue);
if (name.length > 0) {
if (!multimap.hasOwnProperty(name)) {
multimap[name] = [];
}
multimap[name].push(value);
}
});
}
return multimap;
}
var keys = getQueryString(window);
for (var i in keys) {
if (keys.hasOwnProperty(i)) {
for (var z = 0; z < keys[i].length; ++z) {
alert(i + ":" + keys[i][z]);
}
}
}