I have the following data frame:
df <- structure(list(X2 = c("BB_137.HVMSC", "BB_138.combined.HVMSC",
"BB_139.combined.HVMSC", "BB_140.combined.HVMSC", "BB_141.HVMSC",
"BB_142.combined.HMSC-bm")), .Names = "X2", row.names = c(NA,
-6L), class = c("tbl_df", "tbl", "data.frame"))
这看起来像这样
> df
# A tibble: 6 x 1
X2
<chr>
1 BB_137.HVMSC
2 BB_138.combined.HVMSC
3 BB_139.combined.HVMSC
4 BB_140.combined.HVMSC
5 BB_141.HVMSC
6 BB_142.combined.HMSC-bm
我想要做的是将内容分成两列(以
.
作为分隔符),并将最后一个字段保留在第二列。 col1 col2
BB_137 HVMSC
BB_138.combined HVMSC
BB_139.combined HVMSC
BB_140.combined HVMSC
BB_141 HVMSC
BB_142.combined HMSC-bm
如何正确地做到这一点?
我的尝试是这样的:
> df %>% separate(X2, into = c("sid","status", "tiss"), sep = "[.]")
# A tibble: 6 x 3
sid status tiss
* <chr> <chr> <chr>
1 BB_137 HVMSC <NA>
2 BB_138 combined HVMSC
3 BB_139 combined HVMSC
4 BB_140 combined HVMSC
5 BB_141 HVMSC <NA>
6 BB_142 combined HMSC-bm
警告信息: 在第2个位置和第5个位置上的数值过少