1
的列表,并在其他位置包含0
。这可以通过使用列表推导式来轻松完成。def binary_data(data):
return [1 if x in data else 0 for x in range(data[-1] + 1)]
>>> data = [1, 2, 4, 5, 9]
>>> bindata = binary_data(data)
>>> bindata
[0, 1, 1, 0, 1, 1, 0, 0, 0, 1]
step()
看起来更好:import numpy as np
from matplotlib.pyplot import step, show
def binary_data(data):
return [1 if x in data else 0 for x in range(data[-1] + 1)]
data = [1, 2, 4, 5, 9]
bindata = binary_data(data)
xaxis = np.arange(0, data[-1] + 1)
yaxis = np.array(bindata)
step(xaxis, yaxis)
show()
binary_data()
函数:def binary_data(data, yshift=0):
return [yshift+1 if x in data else yshift for x in range(data[-1] + 1)]
现在您可以设置yshift
参数来在y轴上移动数据数组。例如:
>>> data = [1, 2, 4, 5, 9]
>>> bindata1 = binary_data(data)
>>> bindata1
[0, 1, 1, 0, 1, 1, 0, 0, 0, 1]
>>> bindata2 = binary_data(data, 2)
>>> bindata2
[2, 3, 3, 2, 3, 3, 2, 2, 2, 3]
假设你有要叠加绘制的data1
、data2
和data3
,你可以这样实现:
import numpy as np
from matplotlib.pyplot import step, show
def binary_data(data, yshift=0):
return [yshift+1 if x in data else yshift for x in range(data[-1] + 1)]
data1 = [1, 2, 4, 5, 9]
bindata1 = binary_data(data1)
x1 = np.arange(0, data1[-1] + 1)
y1 = np.array(bindata1)
data2 = [1, 4, 9]
bindata2 = binary_data(data2, 2)
x2 = np.arange(0, data2[-1] + 1)
y2 = np.array(bindata2)
data3 = [1, 2, 8, 9]
bindata3 = binary_data(data3, 4)
x3 = np.arange(0, data3[-1] + 1)
y3 = np.array(bindata3)
step(x1, y1, x2, y2, x3, y3)
show()
您可以轻松地编辑它使其适用于任意数量的数据数组:
data = [ [1, 2, 4, 5, 9],
[1, 4, 9],
[1, 2, 8, 9] ]
for shift, d in enumerate(data):
bindata = binary_data(d, 2 * shift)
x = np.arange(0, d[-1] + 1)
y = np.array(bindata)
step(x, y)
show()
最后,如果你正在处理长度不同的数据数组(比如[1,2]
和[15,16]
),而且你不想看到图形在图像中间消失,那么你可以再次调整binary_data()
函数,将其范围强制设置为数据的最大范围。
import numpy as np
from matplotlib.pyplot import step, show
def binary_data(data, limit, yshift=0):
return [yshift+1 if x in data else yshift for x in range(limit)]
data = [ [1, 2, 4, 5, 9, 12, 13, 14],
[1, 4, 10, 11, 20, 21, 22],
[1, 2, 3, 4, 15, 16, 17, 18] ]
# find out the longest data to plot
limit = max( [ x[-1] + 1 for x in data] )
x = np.arange(0, limit)
for shift, d in enumerate(data):
bindata = binary_data(d, limit, 2 * shift)
y = np.array(bindata)
step(x, y)
show()
编辑:如@ImportanceOfBeingErnest所建议的,如果你想在不定义自己的binary_data()
函数的情况下执行data
到bindata
的转换,你可以使用numpy.zeros_like()
。只需在堆叠它们时更加注意:
import numpy as np
from matplotlib.pyplot import step, show
data = [ [1, 2, 4, 5, 9, 12, 13, 14],
[1, 4, 10, 11, 20, 21, 22],
[1, 2, 3, 4, 15, 16, 17, 18] ]
# find out the longest data to plot
limit = max( [ x[-1] + 1 for x in data] )
x = np.arange(0, limit)
for shift, d in enumerate(data):
y = np.zeros_like(x)
y[d] = 1
# don't forget to shift
y += 2*shift
step(x, y)
show()