Jon 建议使用 ArraySegment<T>
,这可能是您想要的内容。但如果您希望表示指向数组内部的指针(就像在 C++ 中一样),请参考下面的代码。此代码不以任何方式跟踪内部指针的“长度”,但如果需要,很容易添加该功能。
免责声明:此代码不提供任何保证,请自行承担风险。
internal struct ArrayPtr<T>
{
public static ArrayPtr<T> Null { get { return default(ArrayPtr<T>); } }
private readonly T[] source;
private readonly int index;
private ArrayPtr(ArrayPtr<T> old, int delta)
{
this.source = old.source;
this.index = old.index + delta;
Debug.Assert(index >= 0);
Debug.Assert(index == 0 || this.source != null && index < this.source.Length);
}
public ArrayPtr(T[] source)
{
this.source = source;
index = 0;
}
public bool IsNull()
{
return this.source == null;
}
public static bool operator <(ArrayPtr<T> a, ArrayPtr<T> b)
{
Debug.Assert(Object.ReferenceEquals(a.source, b.source));
return a.index < b.index;
}
public static bool operator >(ArrayPtr<T> a, ArrayPtr<T> b)
{
Debug.Assert(Object.ReferenceEquals(a.source, b.source));
return a.index > b.index;
}
public static bool operator <=(ArrayPtr<T> a, ArrayPtr<T> b)
{
Debug.Assert(Object.ReferenceEquals(a.source, b.source));
return a.index <= b.index;
}
public static bool operator >=(ArrayPtr<T> a, ArrayPtr<T> b)
{
Debug.Assert(Object.ReferenceEquals(a.source, b.source));
return a.index >= b.index;
}
public static int operator -(ArrayPtr<T> a, ArrayPtr<T> b)
{
Debug.Assert(Object.ReferenceEquals(a.source, b.source));
return a.index - b.index;
}
public static ArrayPtr<T> operator +(ArrayPtr<T> a, int count)
{
return new ArrayPtr<T>(a, +count);
}
public static ArrayPtr<T> operator -(ArrayPtr<T> a, int count)
{
return new ArrayPtr<T>(a, -count);
}
public static ArrayPtr<T> operator ++(ArrayPtr<T> a)
{
return a + 1;
}
public static ArrayPtr<T> operator --(ArrayPtr<T> a)
{
return a - 1;
}
public static implicit operator ArrayPtr<T>(T[] x)
{
return new ArrayPtr<T>(x);
}
public static bool operator ==(ArrayPtr<T> x, ArrayPtr<T> y)
{
return x.source == y.source && x.index == y.index;
}
public static bool operator !=(ArrayPtr<T> x, ArrayPtr<T> y)
{
return !(x == y);
}
public override bool Equals(object x)
{
if (x == null) return this.source == null;
var ptr = x as ArrayPtr<T>?;
if (!ptr.HasValue) return false;
return this == ptr.Value;
}
public override int GetHashCode()
{
unchecked
{
int hash = this.source == null ? 0 : this.source.GetHashCode();
return hash + this.index;
}
}
public T this[int index]
{
get { return source[index + this.index]; }
set { source[index + this.index] = value; }
}
}
现在我们可以做这样的事情:
double[] arr = new double[10];
var p0 = (ArrayPtr<double>)arr;
var p5 = p0 + 5;
p5[0] = 123.4; // sets arr[5] to 123.4
var p7 = p0 + 7;
int diff = p7 - p5; // 2
Tuple<int, int>
中,或者如果您喜欢更具描述性的名称,则可以创建自己的struct
。 - Jon