我有两个LocalTime
对象:
LocalTime l1 = LocalTime.parse("02:53:40");
LocalTime l2 = LocalTime.parse("02:54:27");
我该如何在几分钟内找到它们之间的不同之处?
使用API中描述的until
或between
import java.time.LocalTime;
import static java.time.temporal.ChronoUnit.MINUTES;
public class SO {
public static void main(String[] args) {
LocalTime l1 = LocalTime.parse("02:53:40");
LocalTime l2 = LocalTime.parse("02:54:27");
System.out.println(l1.until(l2, MINUTES));
System.out.println(MINUTES.between(l1, l2));
}
}
->0
0
0
0
自Java 8以来,您可以使用Duration
类。我认为这提供了最优雅的解决方案:
long elapsedMinutes = Duration.between(l1, l2).toMinutes();
我使用 ChronoUnit 来完成这个操作。
long minutesBetween = ChronoUnit.MINUTES.between(l1,l2);
示例
LocalTime localTime=LocalTime.now();
LocalTime localTimeAfter5Minutes=LocalTime.now().plusMinutes(5);
Long minutesBetween=ChronoUnit.MINUTES.between(localTime,localTimeAfter5Minutes);
System.out.println("Diffrence between time in munutes : "+minutesBetween);
输出
Diffrence between time in munutes : 5
long dif = Math.abs (l1.getLocalMillis () - l2.getLocalMillis ());
TimeUnit.MINUTES.convert (dif, TimeUnit.MILLISECONDS);