我创建了一个 Python 代码,用于解决组 Lasso 惩罚线性模型。对于那些不习惯使用这些模型的人来说,基本思想是,您将数据集(x)和响应变量(y)作为输入,以及参数值(lambda1),改变该参数值会改变模型的解。因此,我决定使用 multiprocessing 库并解决不同的模型(与不同的参数值相关联)。我创建了一个名为“model.py”的 python 文件,并包含以下函数:
# -*- coding: utf-8 -*-
from __future__ import division
import functools
import multiprocessing as mp
import numpy as np
from cvxpy import *
def lm_gl_preprocessing(x, y, index, lambda1=None):
lambda_vector = [lambda1]
m = x.shape[1]
n = x.shape[0]
lambda_param = Parameter(sign="positive")
m = m+1
index = np.append(0, index)
x = np.c_[np.ones(n), x]
group_sizes = []
beta_var = []
unique_index = np.unique(index)
for idx in unique_index:
group_sizes.append(len(np.where(index == idx)[0]))
beta_var.append(Variable(len(np.where(index == idx)[0])))
num_groups = len(group_sizes)
group_lasso_penalization = 0
model_prediction = x[:, np.where(index == unique_index[0])[0]] * beta_var[0]
for i in range(1, num_groups):
model_prediction += x[:, np.where(index == unique_index[i])[0]] * beta_var[i]
group_lasso_penalization += sqrt(group_sizes[i]) * norm(beta_var[i], 2)
lm_penalization = (1.0/n) * sum_squares(y - model_prediction)
objective = Minimize(lm_penalization + (lambda_param * group_lasso_penalization))
problem = Problem(objective)
response = {'problem': problem, 'beta_var': beta_var, 'lambda_param': lambda_param, 'lambda_vector': lambda_vector}
return response
def solver(problem, beta_var, lambda_param, lambda_vector):
beta_sol_list = []
for i in range(len(lambda_vector)):
lambda_param.value = lambda_vector[i]
problem.solve(solver=ECOS)
beta_sol = np.asarray(np.row_stack([b.value for b in beta_var])).flatten()
beta_sol_list.append(beta_sol)
return beta_sol_list
def parallel_solver(problem, beta_var, lambda_param, lambda_vector):
# Divide parameter vector into chunks to be executed in parallel
num_chunks = mp.cpu_count()
chunks = np.array_split(lambda_vector, num_chunks)
# Solve problem in parallel
pool = mp.Pool(num_chunks)
global_results = pool.map(functools.partial(solver, problem, beta_var, lambda_param), chunks)
pool.close()
pool.join()
return global_results
- 函数lm_gl_preprocessing基本上使用cvxpy模块定义要解决的模型。
- 函数solver从前一个函数中获取模型详细信息,并解决导致模型最终解决方案的优化问题。
- 函数parallel_solver使用多进程对求解器函数进行并行化处理。
如果在Python控制台中开始运行并行求解器,则会得到一个解决方案。该解决方案与顺序求解器提供的解决方案不同。 如果我重新启动Python控制台并开始运行顺序求解器,然后运行并行求解器,则并行求解器会给出与顺序求解器相同的解决方案。我将展示:
from __future__ import division
from sklearn.datasets import load_boston
import numpy as np
import model as t
boston = load_boston()
x = boston.data
y = boston.target
index = np.array([1, 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5])
lambda1 = 1e-3
r1 = t.lm_gl_preprocessing(x=x, y=y, index=index, lambda1=lambda1)
s_parallel_1 = t.parallel_solver(problem=r1['problem'], beta_var=r1['beta_var'], lambda_param=r1['lambda_param'], lambda_vector=r1['lambda_vector'])
print(s_parallel_1)
[[array([ 4.61648376e+01, -1.22394832e-04, 0.00000000e+00,
0.00000000e+00, 1.37065733e-04, 1.51910696e-03,
0.00000000e+00, 1.51910696e-03, 0.00000000e+00,
7.00079603e-03, 1.52776114e-03, -8.67357376e-01,
7.16429750e-03, -8.67357376e-01])], [], [], []]
s_1 = t.solver(problem=r1['problem'], beta_var=r1['beta_var'], lambda_param=r1['lambda_param'], lambda_vector=r1['lambda_vector'])
print(s_1)
[array([ 3.62813738e+01, -1.06995338e-01, 4.64210526e-02,
1.97112192e-02, 2.68475527e+00, -1.75142155e+01,
3.80741843e+00, 5.14842823e-04, -1.47105323e+00,
3.04949407e-01, -1.23508259e-02, -9.50143293e-01,
9.40708993e-03, -5.25758097e-01])]
#####################################################
r1 = t.lm_gl_preprocessing(x=x, y=y, index=index, lambda1=lambda1)
s_1 = t.solver(problem=r1['problem'], beta_var=r1['beta_var'], lambda_param=r1['lambda_param'], lambda_vector=r1['lambda_vector'])
print(s_1)
[array([ 3.62813738e+01, -1.06995338e-01, 4.64210526e-02,
1.97112192e-02, 2.68475527e+00, -1.75142155e+01,
3.80741843e+00, 5.14842823e-04, -1.47105323e+00,
3.04949407e-01, -1.23508259e-02, -9.50143293e-01,
9.40708993e-03, -5.25758097e-01])]
s_parallel_1 = t.parallel_solver(problem=r1['problem'], beta_var=r1['beta_var'], lambda_param=r1['lambda_param'], lambda_vector=r1['lambda_vector'])
print(s_parallel_1)
[[array([ 3.62813738e+01, -1.06995338e-01, 4.64210526e-02,
1.97112192e-02, 2.68475527e+00, -1.75142155e+01,
3.80741843e+00, 5.14842823e-04, -1.47105323e+00,
3.04949407e-01, -1.23508259e-02, -9.50143293e-01,
9.40708993e-03, -5.25758097e-01])], [], [], []]
PS:我知道在这个例子中,我只是使用并行编程来解决一个可能的参数值的模型,但这只是一个小例子,旨在展示顺序和并行编程所提供的解决方案的差异。由于我在这里完全迷失了,请提供任何提示。
parallel_solver
的输出中,我看到除了一个进程外,所有进程都返回空列表。因此,我猜只有一个进程实际上在执行任务。不知道模型代码的情况下很难回答。我猜测当您调用solver
时,一些参数(例如problem
)会被修改。因此,如果您在solver
之后调用parallel_solver
,则会传递修改后的参数,因此结果会有所不同。 - Amedeononneg=True
而不是sign="positive"
)。 - Amedeo