我正在收集用户输入,格式为“DD/MM/YYYY”
目标是将其作为csv YYYY、MM、DD传递到mktime函数中。
puts "Please enter dob in dd/mm/yyyy format;"
inp = gets.chomp
inp = inp.gsub(" ","")
while inp.length != 10
puts "Please use dd/mm/yyyy format"
inp = gets.chomp
end
bday = inp.gsub("/",",")
ctime = Time.new
btime = Time.mktime(bday)
lsecs = ctime - btime
ysecs = Time.mktime(2001) - Time.mktime(2000)
rsecs = 1000000000 - lsecs
ryears = rsecs / ysecs
puts "You are currently #{lsecs} seconds old"
puts "You have #{ryears} years until you are a billion seconds old!!"
正如您所看到的,唯一剩下的任务是反转用户输入,但很难找到一个紧凑的解决方案。如果您发现了一种方法,请随意帮助缩短此代码。
解决方案:(以秒为单位,年份向下取整/分隔)
def reformat_date(str)
str.split("/").reverse.join(",")
end
puts "Please enter dob in dd/mm/yyyy format;"
inp = gets.chomp
inp = inp.gsub(" ","")
while inp.length != 10
puts "Please use dd/mm/yyyy format"
inp = gets.chomp
inp = inp.gsub(" ","")
end
ctime = Time.new
btime = Time.mktime(reformat_date(inp))
lsecs = ctime - btime
**lsecdel = lsecs.round(0).to_s.reverse.gsub(/...(?=.)/,'\&,').reverse**
ysecs = Time.mktime(2001) - Time.mktime(2000)
rsecs = 1000000000 - lsecs
ryears = rsecs / ysecs
puts "You are currently #{lsecdel} seconds old"
puts "You have #{ryears.round(2)} years until you are a billion seconds old!!"