在这个简单的PyQt演示程序中,我从主线程发出信号。在工作线程中,我连接到它们,但是信号处理程序在主线程中运行:
但是结果显示回调函数在主线程中运行:
这导致以下结果:
from PyQt4 import QtGui, QtCore
import threading
from time import sleep
import sys
class Data():
def __init__(self, a, b):
self.a = a
self.b = b
def __str__(self):
return "Data having %d and %d" % (self.a, self.b)
class Worker(QtCore.QThread):
def __init__(self, parent):
QtCore.QThread.__init__(self)
self.p = parent
def run(self):
self.connect(self.p, QtCore.SIGNAL("newTask"), self.task)
print "[%s] running exec_()" % threading.currentThread()
self.exec_()
def task(self, dataobj):
print "[%s] Processing" % threading.currentThread(), dataobj
sleep(3)
print "Done with", dataobj
self.emit(QtCore.SIGNAL("taskDone"), str(dataobj))
class App(QtCore.QObject):
def __init__(self):
QtCore.QObject.__init__(self)
self.w = Worker(self)
self.connect(self.w, QtCore.SIGNAL("taskDone"), self.on_task_done)
self.w.start()
def assign_tasks(self):
self.emit(QtCore.SIGNAL("newTask"), Data(3, 4))
self.emit(QtCore.SIGNAL("newTask"), Data(5, 6))
print "[%s] Tasks sent" % threading.currentThread()
@staticmethod
def on_task_done(objstr):
print "[%s] App: Worker finished with" % threading.currentThread(), objstr
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
a = App()
sleep(1)
a.assign_tasks()
sleep(20)
sys.exit(app.exec_())
但是结果显示回调函数在主线程中运行:
[<_DummyThread(Dummy-1, started daemon 105564)>] running exec_()
[<_MainThread(MainThread, started 105612)>] Processing Data having 3 and 4
Done with Data having 3 and 4
[<_MainThread(MainThread, started 105612)>] App: Worker finished with Data having 3 and 4
[<_MainThread(MainThread, started 105612)>] Processing Data having 5 and 6
Done with Data having 5 and 6
[<_MainThread(MainThread, started 105612)>] App: Worker finished with Data having 5 and 6
[<_MainThread(MainThread, started 105612)>] Tasks sent
我做错了什么?不幸的是,关于此问题的PyQt文档非常不完整且相互矛盾。
如果我使用moveToThread
技术,我会得到类似的结果:
from PyQt4 import QtGui, QtCore
import threading
from time import sleep
import sys
class Data():
def __init__(self, a, b):
self.a = a
self.b = b
def __str__(self):
return "Data having %d and %d" % (self.a, self.b)
class Worker(QtCore.QObject):
def __init__(self, parent):
QtCore.QObject.__init__(self)
self.connect(parent, QtCore.SIGNAL("newTask"), self.task)
def task(self, dataobj):
print "[%s] Processing" % threading.currentThread(), dataobj
sleep(3)
print "Done with", dataobj
self.emit(QtCore.SIGNAL("taskDone"), str(dataobj))
def start(self):
print "[%s] start()" % threading.currentThread()
class App(QtCore.QObject):
def __init__(self):
QtCore.QObject.__init__(self)
self.w = Worker(self)
self.t = QtCore.QThread(self)
self.w.moveToThread(self.t)
self.connect(self.w, QtCore.SIGNAL("taskDone"), self.on_task_done)
self.connect(self.t, QtCore.SIGNAL("started()"), self.w.start)
self.t.start()
def assign_tasks(self):
self.emit(QtCore.SIGNAL("newTask"), Data(3, 4))
self.emit(QtCore.SIGNAL("newTask"), Data(5, 6))
print "[%s] Tasks sent" % threading.currentThread()
@staticmethod
def on_task_done(objstr):
print "[%s] App: Worker finished with" % threading.currentThread(), objstr
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
a = App()
sleep(1)
a.assign_tasks()
sleep(20)
sys.exit(app.exec_())
这导致以下结果:
[<_DummyThread(Dummy-1, started daemon 108992)>] start()
[<_MainThread(MainThread, started 107004)>] Processing Data having 3 and 4
Done with Data having 3 and 4
[<_MainThread(MainThread, started 107004)>] App: Worker finished with Data having 3 and 4
[<_MainThread(MainThread, started 107004)>] Processing Data having 5 and 6
Done with Data having 5 and 6
[<_MainThread(MainThread, started 107004)>] App: Worker finished with Data having 5 and 6
[<_MainThread(MainThread, started 107004)>] Tasks sent
moveToThread
,通过在Worker.start()
中连接信号而不是在Worker.init()
中连接信号。start()
是工作线程中第一件运行的事情。 我仍然想知道为什么第一个模式不起作用... 我知道“新”的方法不同,但是发生了什么? - jpcgt