如何按名称更改目录的用户和组权限？

Question

os.chown 正是我所需要的，但我希望能够按名称指定用户和组，而不是ID（我不知道它们是什么）。我该如何做到这一点呢？

- mpen

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可能是重复的问题：Python：查找给定用户名/组名的uid/gid（用于os.chown） - Louis

Answer 1

import pwd
import grp
import os

uid = pwd.getpwnam("nobody").pw_uid
gid = grp.getgrnam("nogroup").gr_gid
path = '/tmp/f.txt'
os.chown(path, uid, gid)

- Diego Torres Milano

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我可以在不提供“gid”情况下设置吗？ - alper

根据文档（https://docs.python.org/3/library/os.html#os.chown），只需将ID参数传入-1即可忽略该项。 - josh2112

Answer 2

自Python 3.3以来 https://docs.python.org/3.3/library/shutil.html#shutil.chown

import shutil
shutil.chown(path, user=None, group=None)

更改给定路径的所有者用户和/或组。

用户可以是系统用户名或UID；同样适用于组。

至少需要一个参数。

可用性：Unix。

- Oleg Neumyvakin

Answer 3

由于shutil版本支持组是可选的，因此我将代码复制并粘贴到我的Python2项目中。

https://hg.python.org/cpython/file/tip/Lib/shutil.py#l1010

def chown(path, user=None, group=None):
    """Change owner user and group of the given path.

    user and group can be the uid/gid or the user/group names, and in that case,
    they are converted to their respective uid/gid.
    """

    if user is None and group is None:
        raise ValueError("user and/or group must be set")

    _user = user
    _group = group

    # -1 means don't change it
    if user is None:
        _user = -1
    # user can either be an int (the uid) or a string (the system username)
    elif isinstance(user, basestring):
        _user = _get_uid(user)
        if _user is None:
            raise LookupError("no such user: {!r}".format(user))

    if group is None:
        _group = -1
    elif not isinstance(group, int):
        _group = _get_gid(group)
        if _group is None:
            raise LookupError("no such group: {!r}".format(group))

    os.chown(path, _user, _group)

- guettli

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你应该检查基本字符串吧？ - mpen

Answer 4

您可以使用id -u wong2来获取用户的UID
您也可以使用Python实现：

import os 
def getUidByUname(uname):
    return os.popen("id -u %s" % uname).read().strip()

然后使用该ID来调用os.chown

- wong2