我听说,sleep()会锁定当前的同步方法/块。但是在这里,当我在线程1上调用sleep()时,线程2可以访问相同的块?有人能解释一下吗?
Main.java
public class Main {
public static void main(String args[])
{
Thread1 t1 = new Thread1();
Thread2 t2 = new Thread2();
System.out.println("going to start t1");
t1.start();
System.out.println("going to start t2");
t2.start();
}
}
=====================================================================
Thread1.java
public class Thread1 extends Thread{
public void run() {
Syncc s1 = new Syncc();
s1.me("T1:");
}
}
=====================================================================
Thread2.java
public class Thread2 extends Thread{
public void run() {
Syncc s2 = new Syncc();
s2.me("T2:");
}
}
=====================================================================
Syncc.java
public class Syncc{
public void me(String s){
synchronized(this){
for(int i=0; i<=5; i++)
{
System.out.println(s+" "+" "+i);
try {
Thread.sleep(10000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
输出:
going to start t1
going to start t2
T2: 0
T1: 0
T2: 1
T1: 1
T1: 2
T2: 2
T1: 3
T2: 3
T1: 4
T2: 4
T2: 5
T1: 5
根据sleep()方法,它不应该解锁当前同步块,对吗?如果是这样的话,输出应该是:
开始运行 t1 开始运行 t2
T1: 0
T1: 1
T1: 2
T1: 3
T1: 4
T1: 5
T2: 0
T2: 1
T2: 2
T2: 3
T2: 4
T2: 5
我理解您的意思是:在线程1执行完成后才应该启动线程2,是吗?有什么问题吗?