编辑:
我的第一个回答虽然有效,但并没有遵循MVVM设计原则。我现在提供一种MVVM方法,并将原始答案留在下面供参考。
您可以创建一个行为来解决这个问题。
XAML:
(该段内容无需翻译)
<Menu>
<MenuItem Header="_File" menu:MenuBehavior.MenuItems="{Binding Path=MenuItemViewModels, Mode=OneWay}">
</MenuItem>
</Menu>
视图模型:
public IEnumerable<MenuItemViewModelBase> MenuItemViewModels => new List<MenuItemViewModelBase>
{
new MenuItemViewModel { Header = "Hello" },
new MenuItemSeparatorViewModel(),
new MenuItemViewModel { Header = "World" }
};
Behavior:
public class MenuBehavior
{
public static readonly DependencyProperty MenuItemsProperty =
DependencyProperty.RegisterAttached("MenuItems",
typeof(IEnumerable<MenuItemViewModelBase>), typeof(MenuBehavior),
new FrameworkPropertyMetadata(MenuItemsChanged));
public static IEnumerable<MenuItemViewModelBase> GetMenuItems(DependencyObject element)
{
if (element == null)
{
throw (new ArgumentNullException("element"));
}
return (IEnumerable<MenuItemViewModelBase>)element.GetValue(MenuItemsProperty);
}
public static void SetMenuItems(DependencyObject element, IEnumerable<MenuItemViewModelBase> value)
{
if (element == null)
{
throw (new ArgumentNullException("element"));
}
element.SetValue(MenuItemsProperty, value);
}
private static void MenuItemsChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
var menu = (MenuItem)d;
if (e.OldValue != e.NewValue)
{
menu.ItemsSource = ConvertViewModelsToFrameworkElements((IEnumerable<MenuItemViewModelBase>)e.NewValue);
}
}
private static IEnumerable<FrameworkElement> ConvertViewModelsToFrameworkElements(IEnumerable<MenuItemViewModelBase> viewModels)
{
var frameworkElementList = new List<FrameworkElement>();
foreach (var viewModel in viewModels)
{
switch (viewModel)
{
case MenuItemViewModel mi:
frameworkElementList.Add(new MenuItem
{
Header = mi.Header,
Command = mi.Command,
Icon = mi.Icon
});
break;
case MenuItemSeparatorViewModel s:
frameworkElementList.Add(new Separator());
break;
}
}
return frameworkElementList;
}
}
类:
public class MenuItemViewModelBase
{
}
public class MenuItemViewModel : MenuItemViewModelBase
{
public object Header { get; set; }
public ICommand Command { get; set; }
public object Icon { get; set; }
}
public class MenuItemSeparatorViewModel : MenuItemViewModelBase
{
}
最初的回答:
或者,不要让您的上下文菜单绑定到命令集合,而是将其绑定到FrameworkElements集合,然后您可以直接向集合添加MenuItem或Separator,让Menu控件完成所有模板化操作...
<Style x:Key="DataGridCellStyle" TargetType="{x:Type DataGridCell}">
<Setter Property="ContextMenu">
<Setter.Value>
<ContextMenu ItemsSource="{Binding Commands}" />
</Setter.Value>
</Setter>
</Style>
C#:
this.Commands = new ObservableCollection<FrameworkElement>();
this.Commands.Add(new MenuItem {Header = "Menuitem 2", Command = MainWindow.AddRole1});
this.Commands.Add(new MenuItem {Header = "Menuitem 2", Command = MainWindow.AddRole2});
this.Commands.Add(new MenuItem {Header = "Menuitem 3", Command = MainWindow.AddRole3});
this.Commands.Add(new MenuItem {Header = "Menuitem 4", Command = MainWindow.AddRole4});
this.Commands.Add(new Separator);
this.Commands.Add(new MenuItem {Header = "Menuitem 5", Command = MainWindow.AddRole5});
this.Commands.Add(new MenuItem {Header = "Menuitem 6", Command = MainWindow.AddRole6});
this.Commands.Add(new MenuItem {Header = "Menuitem 7", Command = MainWindow.AddRole7});
我在我的应用程序中使用了这种方法 - 这种分隔符看起来更好。
最初的回答
MenuSeparatorTemplate
。因为它还没有被创建,所以什么也没有显示出来。 - Rachel