我希望您能构建一个多部分请求,其中包含以下参数:name(字符串)、email(字符串)和fileupload(文件)。我正在使用以下Java代码(在Android中工作)。
httppost.getRequestLine()打印出来的是:
httppost.getRequestLine()打印出来的是:
POST http://www.myurl.com/upload HTTP/1.1
客户端的一切看起来都很好,但我的服务器(Django / Apache)将其读取为GET请求,没有GET参数 - request.method
产生'GET',request.GET.items()
生成一个空字典。
我做错了什么?实际上我不知道如何正确设置多部分参数 - 使用的是猜测 - 所以这可能是问题所在。
public void SendMultipartFile() {
Log.e(LOG_TAG, "SendMultipartFile");
DefaultHttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.myurl.com/upload");
File file = new File(Environment.getExternalStorageDirectory(),
"video.3gp");
Log.e(LOG_TAG, "setting up multipart entity");
MultipartEntity mpEntity = new MultipartEntity();
ContentBody cbFile = new FileBody(file);
mpEntity.addPart("fileupload", cbFile);
Log.i("SendLargeFile", "file length = " + file.length());
try {
mpEntity.addPart("name", new StringBody(name));
mpEntity.addPart("email", new StringBody(email));;
} catch (UnsupportedEncodingException e1) {
// TODO Auto-generated catch block
Log.e(LOG_TAG, "UnsupportedEncodingException");
e1.printStackTrace();
}
httppost.setEntity(mpEntity);
Log.e(LOG_TAG, "executing request " + httppost.getRequestLine());
HttpResponse response;
try {
Log.e(LOG_TAG, "about to execute");
response = httpclient.execute(httppost);
Log.e(LOG_TAG, "executed");
HttpEntity resEntity = response.getEntity();
Log.e(LOG_TAG, response.getStatusLine().toString());
if (resEntity != null) {
System.out.println(EntityUtils.toString(resEntity));
}
if (resEntity != null) {
resEntity.consumeContent();
}
} catch (ClientProtocolException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}