我该如何在WPF中绘制一个凹角矩形?
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请点击此处查看博客文章http://jobijoy.blogspot.com/2008/11/concave-cornered-rectangle-blend-tip.html
另一种方法是创建一个WPF自定义形状,如下所示:
public class ConcaveRectangle:System.Windows.Shapes.Shape
do you mean a rectangle with concave corners?, ie:
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给定一个长宽分别为 w x h
,拥有圆角半径 r
的矩形。
该矩形有4个角:
A : 0,0
B : w,0
C : w,h
D : 0,h
有一个隐含的最小尺寸
w = 2r
h = 2r
有4个圆心,A,B,C,D
因此,存在一个边缘点的网格:
(0,0)--(0+r,0)---(w-r,0)---(w,0)
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(0,0+r) (w,0+r)
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(0,h-r) (w,h-r)
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(0,h)--(0+r,h)---(w-r,h)---(w,h)