在PHP中对两个数组值求和

Question

我有两个 cookie，它们的值如下：

foreach($_COOKIE as $key=>$val) {
    $piece = explode(",", $val);
    $t_cost = array($piece[3]);
    print_r($t_cost); //It prints Array ( [0] => 11 ) Array ( [0] => 11 )
    echo $total_cost = array_sum($t_cost);
}

但它只打印一个值。我该如何将两个值加起来并进行求和？

- user1928251

---

将每个值($t_cost)推入一个新数组，然后在该数组上应用数组求和操作？ - ka_lin

Answer 1

我认为你不需要使用array_sum，只需使用+=运算符即可节省一些内存。

$t_cost = 0;
foreach($_COOKIE as $key=>$val) {
    $piece = explode(",", $val);
    $t_cost += $piece[3];
}
echo $t_cost;

- AZinkey

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这是如何工作的呢？因为它有效，你能解释一下吗？ - user1928251

Answer 2

实际上不需要使用array_sum。

// the array where all piece[3] values are stored
$t_cost = array();

// loop through array
// just foreach($_COOKIE as $val) is enough
foreach($_COOKIE as $key=>$val) {

    // split by comma
    $piece = explode(",", $val);

    // add to array
    $t_cost[] = $piece[3];

}
// sum up  
$total_cost = array_sum($t_cost);   

或者仅仅是。

$total = 0;
foreach($_COOKIE as $key=>$val) {
        $piece = explode(",", $val);  
        $total += $piece[3];
}
echo $total;

- Akshay Hegde

Answer 3

$total = 0;
foreach($_COOKIE as $key=>$val) {
      $piece = explode(",", $val);
      $t_cost = trim(str_replace('$', '', array($piece[3]));
      $total += (float)$t_cost;
      echo "The total cost: $".$total;
}

- Jeff Mattson