我正在尝试以编程方式检索iPhone应用程序在任何时候使用的内存量。是的,我知道ObjectAlloc / Leaks。我对此不感兴趣,只想知道是否可以编写一些代码并获取正在使用的字节数,并通过NSLog报告它。
谢谢。
我正在尝试以编程方式检索iPhone应用程序在任何时候使用的内存量。是的,我知道ObjectAlloc / Leaks。我对此不感兴趣,只想知道是否可以编写一些代码并获取正在使用的字节数,并通过NSLog报告它。
谢谢。
要获取你的应用程序实际使用的内存字节,你可以像下面的示例一样进行操作。然而,你真的应该熟悉各种分析工具,因为它们旨在为你提供更好的整体使用情况图像。
#import <mach/mach.h>
// ...
void report_memory(void) {
struct task_basic_info info;
mach_msg_type_number_t size = TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %lu", info.resident_size);
NSLog(@"Memory in use (in MiB): %f", ((CGFloat)info.resident_size / 1048576));
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
结构体info.virtual_size中还有一个字段,它将给出可用虚拟内存的字节数(或者说是分配给您的应用程序作为潜在虚拟内存的内存)。pgb链接到的代码将为您提供设备可用的内存量以及内存类型。
这已在2019年7月1日在Mojave 10.4.6上使用Xcode 11进行了测试,并在2020年11月5日作为Xcode 11.3的一部分进行了测试。
所有之前的答案都返回错误的结果。
下面是两个Swift
版本。
以下是如何获得由苹果公司的Quinn “The Eskimo!”编写的预期值。
这使用了从Darwin > Mach > task_info
中的phys_footprint
变量,并且与Xcode调试导航器中的内存计量值非常接近。
返回的值以字节为单位。
https://forums.developer.apple.com/thread/105088#357415
以下是原始代码。
func memoryFootprint() -> mach_vm_size_t? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
return info.phys_footprint
}
稍微修改一下,创建一个Swift方法的类级别集合,可以轻松地返回实际字节数和以MB为单位格式化输出的显示。我将其作为自动化UITest套件的一部分使用,记录同一测试的多个迭代之前和之后使用的内存,以查看是否存在任何潜在的泄漏或需要调查的分配。
// Created by Alex Zavatone on 8/1/19.
//
class Memory: NSObject {
// From Quinn the Eskimo at Apple.
// https://forums.developer.apple.com/thread/105088#357415
class func memoryFootprint() -> Float? {
// The `TASK_VM_INFO_COUNT` and `TASK_VM_INFO_REV1_COUNT` macros are too
// complex for the Swift C importer, so we have to define them ourselves.
let TASK_VM_INFO_COUNT = mach_msg_type_number_t(MemoryLayout<task_vm_info_data_t>.size / MemoryLayout<integer_t>.size)
let TASK_VM_INFO_REV1_COUNT = mach_msg_type_number_t(MemoryLayout.offset(of: \task_vm_info_data_t.min_address)! / MemoryLayout<integer_t>.size)
var info = task_vm_info_data_t()
var count = TASK_VM_INFO_COUNT
let kr = withUnsafeMutablePointer(to: &info) { infoPtr in
infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { intPtr in
task_info(mach_task_self_, task_flavor_t(TASK_VM_INFO), intPtr, &count)
}
}
guard
kr == KERN_SUCCESS,
count >= TASK_VM_INFO_REV1_COUNT
else { return nil }
let usedBytes = Float(info.phys_footprint)
return usedBytes
}
class func formattedMemoryFootprint() -> String
{
let usedBytes: UInt64? = UInt64(self.memoryFootprint() ?? 0)
let usedMB = Double(usedBytes ?? 0) / 1024 / 1024
let usedMBAsString: String = "\(usedMB)MB"
return usedMBAsString
}
}
享受!
注意:一个有进取心的编码者可能想要向该类添加静态格式化程序,以使usedMBAsString
仅返回2位有效小数。
NEPacketTunnelProvider
扩展的唯一解决方案)。 - Top-MasterTASK_BASIC_INFO
的头文件如下:
/* Don't use this, use MACH_TASK_BASIC_INFO instead */
void report_memory(void)
{
struct mach_task_basic_info info;
mach_msg_type_number_t size = MACH_TASK_BASIC_INFO_COUNT;
kern_return_t kerr = task_info(mach_task_self(),
MACH_TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
NSLog(@"Memory in use (in bytes): %u", info.resident_size);
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
}
这里是 report_memory() 的增强版,可以快速在 NSLog() 中显示泄漏状态。
void report_memory(void) {
static unsigned last_resident_size=0;
static unsigned greatest = 0;
static unsigned last_greatest = 0;
struct task_basic_info info;
mach_msg_type_number_t size = sizeof(info);
kern_return_t kerr = task_info(mach_task_self(),
TASK_BASIC_INFO,
(task_info_t)&info,
&size);
if( kerr == KERN_SUCCESS ) {
int diff = (int)info.resident_size - (int)last_resident_size;
unsigned latest = info.resident_size;
if( latest > greatest ) greatest = latest; // track greatest mem usage
int greatest_diff = greatest - last_greatest;
int latest_greatest_diff = latest - greatest;
NSLog(@"Mem: %10u (%10d) : %10d : greatest: %10u (%d)", info.resident_size, diff,
latest_greatest_diff,
greatest, greatest_diff );
} else {
NSLog(@"Error with task_info(): %s", mach_error_string(kerr));
}
last_resident_size = info.resident_size;
last_greatest = greatest;
}
Jason Coco的答案的Swift解决方案:
func reportMemory() {
let name = mach_task_self_
let flavor = task_flavor_t(TASK_BASIC_INFO)
let basicInfo = task_basic_info()
var size: mach_msg_type_number_t = mach_msg_type_number_t(sizeofValue(basicInfo))
let pointerOfBasicInfo = UnsafeMutablePointer<task_basic_info>.alloc(1)
let kerr: kern_return_t = task_info(name, flavor, UnsafeMutablePointer(pointerOfBasicInfo), &size)
let info = pointerOfBasicInfo.move()
pointerOfBasicInfo.dealloc(1)
if kerr == KERN_SUCCESS {
print("Memory in use (in bytes): \(info.resident_size)")
} else {
print("error with task info(): \(mach_error_string(kerr))")
}
}
Swift 3.1 (As of August 8, 2017)
func getMemory() {
var taskInfo = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout<mach_task_basic_info>.size)/4
let kerr: kern_return_t = withUnsafeMutablePointer(to: &taskInfo) {
$0.withMemoryRebound(to: integer_t.self, capacity: 1) {
task_info(mach_task_self_, task_flavor_t(MACH_TASK_BASIC_INFO), $0, &count)
}
}
if kerr == KERN_SUCCESS {
let usedMegabytes = taskInfo.resident_size/(1024*1024)
print("used megabytes: \(usedMegabytes)")
} else {
print("Error with task_info(): " +
(String(cString: mach_error_string(kerr), encoding: String.Encoding.ascii) ?? "unknown error"))
}
}
(1024*1024)
而不是1000000
,才能从字节得到兆字节。 - ivanzoid以下是Swift 3版本:
func mach_task_self() -> task_t {
return mach_task_self_
}
func getMegabytesUsed() -> Float? {
var info = mach_task_basic_info()
var count = mach_msg_type_number_t(MemoryLayout.size(ofValue: info) / MemoryLayout<integer_t>.size)
let kerr = withUnsafeMutablePointer(to: &info) { infoPtr in
return infoPtr.withMemoryRebound(to: integer_t.self, capacity: Int(count)) { (machPtr: UnsafeMutablePointer<integer_t>) in
return task_info(
mach_task_self(),
task_flavor_t(MACH_TASK_BASIC_INFO),
machPtr,
&count
)
}
}
guard kerr == KERN_SUCCESS else {
return nil
}
return Float(info.resident_size) / (1024 * 1024)
}
size_t memoryFootprint()
{
task_vm_info_data_t vmInfo;
mach_msg_type_number_t count = TASK_VM_INFO_COUNT;
kern_return_t result = task_info(mach_task_self(), TASK_VM_INFO, (task_info_t) &vmInfo, &count);
if (result != KERN_SUCCESS)
return 0;
return static_cast<size_t>(vmInfo.phys_footprint);
}