我正在尝试创建一个通用函数,用于替换嵌套字典中的键中的点号。我有一个非通用函数,可以实现三级深度,但一定有一种通用的方法。欢迎任何帮助!
output = {'key1': {'key2': 'value2', 'key3': {'key4 with a .': 'value4', 'key5 with a .': 'value5'}}}
def print_dict(d):
new = {}
for key,value in d.items():
new[key.replace(".", "-")] = {}
if isinstance(value, dict):
for key2, value2 in value.items():
new[key][key2] = {}
if isinstance(value2, dict):
for key3, value3 in value2.items():
new[key][key2][key3.replace(".", "-")] = value3
else:
new[key][key2.replace(".", "-")] = value2
else:
new[key] = value
return new
print print_dict(output)
更新:为了回答我的问题,我使用了json object_hooks创建了一个解决方案:
import json
def remove_dots(obj):
for key in obj.keys():
new_key = key.replace(".","-")
if new_key != key:
obj[new_key] = obj[key]
del obj[key]
return obj
output = {'key1': {'key2': 'value2', 'key3': {'key4 with a .': 'value4', 'key5 with a .': 'value5'}}}
new_json = json.loads(json.dumps(output), object_hook=remove_dots)
print new_json