从一个字符串中获取URL

Question

最近我一直在寻找一种用PHP从字符串中获取URL的代码。我基本上是想从消息中获取缩短的URL，然后稍后进行HEAD请求以找到实际链接。

有人有返回字符串中URL的代码吗？

提前感谢。

为Ghost Dog编辑:

这是我正在解析的样本：

$test = "I am testing this application for http://test.com YAY!";

以下是我得到的解决方案:

$regex = '$\b(https?|ftp|file)://[-A-Z0-9+&@#/%?=~_|!:,.;]*[-A-Z0-9+&@#/%=~_|]$i';

preg_match_all($regex, $string, $result, PREG_PATTERN_ORDER);
$A = $result[0];

foreach($A as $B)
{
    $URL = GetRealURL($B);
    echo "$URL<BR>";    
}


function GetRealURL( $url ) 
{ 
    $options = array(
        CURLOPT_RETURNTRANSFER => true,
        CURLOPT_HEADER         => true,
        CURLOPT_FOLLOWLOCATION => true,
        CURLOPT_ENCODING       => "",
        CURLOPT_USERAGENT      => "spider",
        CURLOPT_AUTOREFERER    => true,
        CURLOPT_CONNECTTIMEOUT => 120,
        CURLOPT_TIMEOUT        => 120,
        CURLOPT_MAXREDIRS      => 10,
    ); 

    $ch      = curl_init( $url ); 
    curl_setopt_array( $ch, $options ); 
    $content = curl_exec( $ch ); 
    $err     = curl_errno( $ch ); 
    $errmsg  = curl_error( $ch ); 
    $header  = curl_getinfo( $ch ); 
    curl_close( $ch ); 
    return $header['url']; 
} 

请查看详细答案。

- Tyler Carter

---

你可以展示一下你正在解析的内容的示例吗？ - ghostdog74

Answer 1

这段代码可能会有帮助（请参阅MadTechie的最新帖子）：

http://www.phpfreaks.com/forums/index.php/topic,245248.msg1146218.html#msg1146218

<?php
$string = "some random text http://tinyurl.com/9uxdwc some http://google.com random text http://tinyurl.com/787988";

$regex = '$\b(https?|ftp|file)://[-A-Z0-9+&@#/%?=~_|!:,.;]*[-A-Z0-9+&@#/%=~_|]$i';

preg_match_all($regex, $string, $result, PREG_PATTERN_ORDER);
$A = $result[0];

foreach($A as $B)
{
   $URL = GetRealURL($B);
   echo "$URL<BR>";   
}


function GetRealURL( $url ) 
{ 
   $options = array(
      CURLOPT_RETURNTRANSFER => true,
      CURLOPT_HEADER         => true,
      CURLOPT_FOLLOWLOCATION => true,
      CURLOPT_ENCODING       => "",
      CURLOPT_USERAGENT      => "spider",
      CURLOPT_AUTOREFERER    => true,
      CURLOPT_CONNECTTIMEOUT => 120,
      CURLOPT_TIMEOUT        => 120,
      CURLOPT_MAXREDIRS      => 10,
   ); 

   $ch      = curl_init( $url ); 
   curl_setopt_array( $ch, $options ); 
   $content = curl_exec( $ch ); 
   $err     = curl_errno( $ch ); 
   $errmsg  = curl_error( $ch ); 
   $header  = curl_getinfo( $ch ); 
   curl_close( $ch ); 
   return $header['url']; 
}  

?>

- jimyi

Answer 2

类似以下这样：

$matches = array();
preg_match_all('/http:\/\/[a-zA-Z0-9.-]+\/[a-zA-Z0-9.-]+/', $text, $matches);
print_r($matches);

您需要调整正则表达式以获得所需内容。

为了获取URL，请考虑使用以下简单方法：

curl -I http://url.com/path | grep Location: | awk '{print $2}'

- gahooa