这个概念看起来很容易解释,但是实际上实现起来有点困难(“正确地”)。
简而言之,我想运行多个函数,并将它们的输出推送到单个通道中。
作为一个带有多个通道的样本工作测试,以阐明我的问题: https://play.golang.org/p/1ztCvPFLXKv
package main
import (
"fmt"
"time"
)
type intTest struct {
ID int
Number int
}
func modify1(channelID string, res chan []intTest) {
s := []intTest{}
for i := 0; i < 10; i++ {
fmt.Printf("Adding inside: %s\n", channelID)
s = append(s, intTest{i, 0})
time.Sleep(100 * time.Millisecond)
}
res <- s
}
func modify2(channelID string, res chan []intTest) {
s := []intTest{}
for i := 10; i < 20; i++ {
fmt.Printf("Adding inside: %s\n", channelID)
s = append(s, intTest{i, 0})
time.Sleep(200 * time.Millisecond)
}
res <- s
}
func modify3(channelID string, res chan []intTest) {
s := []intTest{}
for i := 20; i < 30; i++ {
fmt.Printf("Adding inside: %s\n", channelID)
s = append(s, intTest{i, 0})
time.Sleep(300 * time.Millisecond)
}
res <- s
}
func main() {
channelA := make(chan []intTest)
channelB := make(chan []intTest)
channelC := make(chan []intTest)
go modify1("A", channelA)
go modify2("B", channelB)
go modify3("C", channelC)
b := append(<-channelA, <-channelB...)
b = append(b, <-channelC...)
fmt.Println(b)
}
输出:
Adding inside: C
Adding inside: A
Adding inside: B
..snip..
Adding inside: C
Adding inside: C
Adding inside: C
[{0 0} {1 0} {2 0} {3 0} {4 0} {5 0} {6 0} {7 0} {8 0} {9 0} {10 0} {11 0} {12 0} {13 0} {14 0} {15 0} {16 0} {17 0} {18 0} {19 0} {20 0} {21 0} {22 0} {23 0} {24 0} {25 0} {26 0} {27 0} {28 0} {29 0}]
然而,我想要实现类似这样的效果:https://play.golang.org/p/qvC88LwkanY 输出结果:
Adding inside: C
Adding inside: A
Adding inside: B
..snip
Adding inside: B
Adding inside: A
Adding inside: C
[{0 0} {1 0} {2 0} {3 0} {4 0} {5 0} {6 0} {7 0} {8 0} {9 0}]
但是,如图所示,函数modify2和modify3似乎从未被添加。
这种情况是否可能发生,还是上面的示例更可行?