如何在安卓中使用GSON解析JSON数据

14
我正在使用GSON解析Json数据。我的Json数据如下:
{
    "count": "12",
    "colbreak": 1,
    "name": "unary rels",
    "score": "9090",
    "Words": [
        {
            "count": 6,
            "word": "prp_għaċ-",
            "name": "prp_għaċ-",
            "score": 9.1,
            "Words": "kol",
            "seek": 2231297
        }
    ],
    "seek": 0
}

GsonParse.java

public class GsonParse {


 @SerializedName("count")
 public String count;

 @SerializedName("colbreak")
 public String colbreak;

 @SerializedName("name")
 public String count;
 @SerializedName("score")
 public String score;

 @SerializedName("Words")
 public List<Words> mWords = new ArrayList<Words>();

 @SerializedName("seek")
 public String seek;
}

我正在使用以下方法解析这个JSON数据。
public static <T> ArrayList<T> JsonParse(T t, String response) {
        // convert String into InputStream
        InputStream in = new ByteArrayInputStream(response.getBytes());
        JsonReader reader;
        ArrayList<T> lcs = new ArrayList<T>();
        try {
            reader = new JsonReader(new InputStreamReader(in, "UTF-8"));
            Gson gson = new Gson();

            reader.beginObject();
            while (reader.hasNext()) {

                T cse = (T) gson.fromJson(reader, t.getClass());
                lcs.add(cse);
            }

            reader.endObject();

            /*
             * reader.nextName(); reader.nextString(); reader.nextName();
             * reader.nextString();
             */
            reader.close();
        } catch (UnsupportedEncodingException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return (ArrayList<T>) lcs;
    }

我遇到了以下错误。
03-31 10:14:26.968: E/AndroidRuntime(18578): com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was NAME at line 1 column 73

1
请发布错误日志。 - Siddharth_Vyas
请同时发布 Words 类。 - sakura
@Sid 怎么解析这个 JSON 字符串? - dipali
5个回答

21

你可以尝试像这样读取gson的值:

try {
      AssetManager assetManager = getAssets();
  InputStream ims = assetManager.open("file.txt");

  Gson gson = new Gson();
  Reader reader = new InputStreamReader(ims);

  GsonParse gsonObj = gson.fromJson(reader, GsonParse.class);

     }catch(IOException e) {
       e.printStackTrace();
 }

假设您只收到此单个块而不是列表,并且此数据当前位于资产文件夹中的文件中。您可以将其更改为要从中读取的流。

您使用的类应该如下所示:

GsonParse.class

public class GsonParse {
 @SerializedName("count")
 private String count;

 @SerializedName("colbreak")
 private String colbreak;

 @SerializedName("name")
 private String name;

 @SerializedName("score")
 private String score;

 @SerializedName("Words")
 private List<Words> mWords = new ArrayList<Words>();

 @SerializedName("seek")
 private String seek;

public String getCount() {
    return count;
}

public void setCount(String count) {
    this.count = count;
}

public String getColbreak() {
    return colbreak;
}

public void setColbreak(String colbreak) {
    this.colbreak = colbreak;
}

private String getName() {
    return name;
}

private void setName(String name) {
    this.name = name;
}

public String getScore() {
    return score;
}

public void setScore(String score) {
    this.score = score;
}

public List<Words> getmWords() {
    return mWords;
}

public void setmWords(List<Words> mWords) {
    this.mWords = mWords;
}

public String getSeek() {
    return seek;
}

public void setSeek(String seek) {
    this.seek = seek;
}
}

Words.class

public class Words {
@SerializedName(value ="count")
private String count;
@SerializedName(value="word")
private String word;
@SerializedName(value="score")
private String name;
@SerializedName(value="Words")
private String words;
@SerializedName(value="seek")
private String seek;

    public String getCount() {
    return count;
}
public void setCount(String count) {
    this.count = count;
}
public String getWord() {
    return word;
}
public void setWord(String word) {
    this.word = word;
}
public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
public String getWords() {
    return words;
}
public void setWords(String words) {
    this.words = words;
}
public String getSeek() {
    return seek;
}
public void setSeek(String seek) {
    this.seek = seek;
}
}

在words.class中缺失了一个参数,您可以添加它。

GSON不直接支持UTF-8字符。因此,使用http接收响应时,您需要将其转换为utf-8格式在http响应本身中。

您可以尝试使用:

String jsonString = new Gson().toJson(objectToEncode);
byte[] utf8JsonString = jsonString.getBytes("UTF8");
responseToClient.write(utf8JsonString, 0, utf8JsonString.Length);

Gson不使用get/set,为什么要创建它们?至少如果你想添加get/set,那就把字段设为私有的。 - Marco Acierno
@MarcoAcierno 是的,gson不使用它们,但只是为了获取数据 :)..正确的做法是将它们设为私有。我只是简单地选择了用户的类 :)..我会更改的.. :) - Rat-a-tat-a-tat Ratatouille

9

你好,使用以下Gradle库:

compile 'com.google.code.gson:gson:2.2.4'

JSON类

import java.util.List;
public class GsonParse{

/**
 * count : 12
 * colbreak : 1
 * name : unary rels
 * score : 9090
 * Words : [{"count":6,"word":"prp_għaċ-","name":"prp_għaċ-","score":9.1,"Words":"kol","seek":2231297}]
 * seek : 0
 */

private String count;
private int colbreak;
private String name;
private String score;
private int seek;
/**
 * count : 6
 * word : prp_għaċ-
 * name : prp_għaċ-
 * score : 9.1
 * Words : kol
 * seek : 2231297
 */

private List<WordsBean> Words;

public String getCount() {
    return count;
}

public void setCount(String count) {
    this.count = count;
}

public int getColbreak() {
    return colbreak;
}

public void setColbreak(int colbreak) {
    this.colbreak = colbreak;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public String getScore() {
    return score;
}

public void setScore(String score) {
    this.score = score;
}

public int getSeek() {
    return seek;
}

public void setSeek(int seek) {
    this.seek = seek;
}

public List<WordsBean> getWords() {
    return Words;
}

public void setWords(List<WordsBean> Words) {
    this.Words = Words;
}

public static class WordsBean {
    private int count;
    private String word;
    private String name;
    private double score;
    private String Words;
    private int seek;

    public int getCount() {
        return count;
    }

    public void setCount(int count) {
        this.count = count;
    }

    public String getWord() {
        return word;
    }

    public void setWord(String word) {
        this.word = word;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public double getScore() {
        return score;
    }

    public void setScore(double score) {
        this.score = score;
    }

    public String getWords() {
        return Words;
    }

    public void setWords(String Words) {
        this.Words = Words;
    }

    public int getSeek() {
        return seek;
    }

    public void setSeek(int seek) {
        this.seek = seek;
    }
}

调用API将响应放入以下代码并检索数据

GsonParse gsonparse = gson.fromJson(response, GsonParse.class);
//gsonparse.getWords() // It will returns list of Words
//Also do loop and get more data using data
gsonparse.getColbreak();
gsonparse.getSeek();
for (GsonParse.WordsBean data:gsonparse.getWords())
{

    data.getName();

}

希望这对您有所帮助。

在获取数据时出现警告。 - ashish

3
替换
@SerializedName("name")
public String count;

with

@SerializedName("name")
public String name;

我猜问题出在您同时使用了@SerializedName("count")@SerializedName("name")来表示public String count;。谢谢。

3
让我感到惊讶的是,为什么用户没有收到编译时错误提示,指出count已经被定义了? - Rat-a-tat-a-tat Ratatouille

2

试试这个:

JSONArray jsonarray = jsonObject.getJSONArray("responseData");
Type listType = new TypeToken<ArrayList<AllUsers>>(){}.getType();
List<AllUsers> allUserses = 
    new GsonBuilder().create().fromJson(jsonarray.toString(), listType);

for(AllUsers user: allUserses){
         allUsersDao.insertOrReplace(user);
}

2
尝试格式化您的代码,我猜一些解释也不会有害。 - Iulian Popescu

0

你的代码中缺少很多东西...

请看下面的代码并尝试使用它...

import java.util.List;

public class GsonParse {

    public GsonParse() {
    }

    public String count = "";
    public String colbreak = "";
    public String name = "";
    public String score = "";
    public int seek = 0;
    List<WordsData> Words;

    public String getCount() {
        return count;
    }

    public void setCount(String count) {
        this.count = count;
    }

    public String getColbreak() {
        return colbreak;
    }

    public void setColbreak(String colbreak) {
        this.colbreak = colbreak;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getScore() {
        return score;
    }

    public void setScore(String score) {
        this.score = score;
    }

    public int getSeek() {
        return seek;
    }

    public void setSeek(int seek) {
        this.seek = seek;
    }

    public List<WordsData> getWords() {
        return Words;
    }

    public void setWords(List<WordsData> words) {
        Words = words;
    }

    public class WordsData {

        public WordsData() {
        }

        public int count = 0;
        public String word = "";
        public String name = "";
        public double score = 0.0;
        public String Words = "";
        public int seek = 0;

        public int getCount() {
            return count;
        }

        public void setCount(int count) {
            this.count = count;
        }

        public String getWord() {
            return word;
        }

        public void setWord(String word) {
            this.word = word;
        }

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name;
        }

        public double getScore() {
            return score;
        }

        public void setScore(double score) {
            this.score = score;
        }

        public String getWords() {
            return Words;
        }

        public void setWords(String words) {
            Words = words;
        }

        public int getSeek() {
            return seek;
        }

        public void setSeek(int seek) {
            this.seek = seek;
        }
    }

}

更多细节请查看示例


@dipali,只有当JSON字段名与实例变量名不同时,您才需要使用“@serializedName”。当字段名与实例变量名完全匹配时,gson足够聪明,可以自动识别。 - BeccaP

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