PHP与命令行程序的交互

3
我有一个命令行程序,它通过流而不是命令行参数输入数据。(例如,一个使用scanf()函数进行输入的C程序)。我该如何使用PHP与该应用程序交互?由于输入不是通过命令行参数传递的,因此exec()和shell_exec()函数在这里无法派上用场。我需要在PHP脚本和命令行程序之间建立一个持续的输入/输出连接,以便用户可以将输入提供给PHP,PHP将其中转给程序并获取输出,然后将输出显示给用户。
1个回答

2
你可以使用 proc_open 来实现此功能。
以下是该页面上的示例:
<?php
$descriptorspec = array(
   0 => array("pipe", "r"),  // stdin is a pipe that the child will read from
   1 => array("pipe", "w"),  // stdout is a pipe that the child will write to
   2 => array("file", "/tmp/error-output.txt", "a") // stderr is a file to write to
);

$cwd = '/tmp';
$env = array('some_option' => 'aeiou');

$process = proc_open('php', $descriptorspec, $pipes, $cwd, $env);

if (is_resource($process)) {
    // $pipes now looks like this:
    // 0 => writeable handle connected to child stdin
    // 1 => readable handle connected to child stdout
    // Any error output will be appended to /tmp/error-output.txt

    fwrite($pipes[0], '<?php print_r($_ENV); ?>');
    fclose($pipes[0]);

    echo stream_get_contents($pipes[1]);
    fclose($pipes[1]);

    // It is important that you close any pipes before calling
    // proc_close in order to avoid a deadlock
    $return_value = proc_close($process);

    echo "command returned $return_value\n";
}
?>

输出:

Array
(
    [some_option] => aeiou
    [PWD] => /tmp
    [SHLVL] => 1
    [_] => /usr/local/bin/php
)
command returned 0

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