我想知道是否可以从CLPlacemark获取州的缩写?
在苹果的CLPlacemark参考文献中，它指出：
administrativeArea 与地标相关联的州或省份。(只读) @property(nonatomic, readonly) NSString *administrativeArea 讨论 例如，如果地标位置是苹果公司总部，则此属性的值将为字符串“CA”或“加利福尼亚州”。
但是，无论何时我使用它，我只得到完整的州（即加利福尼亚州），而不是缩写（即CA）。有人可以帮我吗？
7个回答
35
针对其他需要解决此问题的人，我已经为 CLPlacemark 创建了一个类别类，该类别类返回短状态字符串。你只需要调用 myPlacemark shortState 即可。
CLPlacemark+ShortState.h
#import <CoreLocation/CoreLocation.h>
#import <Foundation/Foundation.h>
@interface CLPlacemark (ShortState)
- (NSString *)shortState;
@end
CLPlacemark+ShortState.m
#import "CLPlacemark+ShortState.h"
@interface CLPlacemark (ShortStatePrivate)
- (NSDictionary *)nameAbbreviations;
@end
@implementation CLPlacemark (ShortState)
- (NSString *)shortState {
NSString *state = [self.administrativeArea lowercaseString];
if (state.length==0)
return nil;
return [[self nameAbbreviations] objectForKey:state];
}
- (NSDictionary *)nameAbbreviations {
static NSDictionary *nameAbbreviations = nil;
static dispatch_once_t onceToken;
dispatch_once(&onceToken, ^{
nameAbbreviations = [NSDictionary dictionaryWithObjectsAndKeys:
@"AL",@"alabama",
@"AK",@"alaska",
@"AZ",@"arizona",
@"AR",@"arkansas",
@"CA",@"california",
@"CO",@"colorado",
@"CT",@"connecticut",
@"DE",@"delaware",
@"DC",@"district of columbia",
@"FL",@"florida",
@"GA",@"georgia",
@"HI",@"hawaii",
@"ID",@"idaho",
@"IL",@"illinois",
@"IN",@"indiana",
@"IA",@"iowa",
@"KS",@"kansas",
@"KY",@"kentucky",
@"LA",@"louisiana",
@"ME",@"maine",
@"MD",@"maryland",
@"MA",@"massachusetts",
@"MI",@"michigan",
@"MN",@"minnesota",
@"MS",@"mississippi",
@"MO",@"missouri",
@"MT",@"montana",
@"NE",@"nebraska",
@"NV",@"nevada",
@"NH",@"new hampshire",
@"NJ",@"new jersey",
@"NM",@"new mexico",
@"NY",@"new york",
@"NC",@"north carolina",
@"ND",@"north dakota",
@"OH",@"ohio",
@"OK",@"oklahoma",
@"OR",@"oregon",
@"PA",@"pennsylvania",
@"RI",@"rhode island",
@"SC",@"south carolina",
@"SD",@"south dakota",
@"TN",@"tennessee",
@"TX",@"texas",
@"UT",@"utah",
@"VT",@"vermont",
@"VA",@"virginia",
@"WA",@"washington",
@"WV",@"west virginia",
@"WI",@"wisconsin",
@"WY",@"wyoming",
nil];
});
return nameAbbreviations;
}
@end
- ChrisH
3
1谢谢！我认为这对未来使用/浏览此内容的访问者来说可能非常有用！ - sridvijay
1感谢您在原问题发布之后很久还接受了它，希望这对某人确实有用。 - ChrisH
2嘿，我把它转换成了一个包括加拿大省份的plist。更加简洁+您可以添加更多内容（只需从文件中加载字典而不是在代码中编写）。这种方法非常棒。
http://cl.ly/3c0W1s3E1J1Y - shim
5
我认为你可能无法获取各州的缩写，但是你可以自己创建一个类来实现这个功能。
- 列出所有的州（州是标准）
- 比较这些州并返回它们的缩写
代码..
类 StateAbbreviation
StateAbbreviation.h
@interface StateAbbreviation : NSString {
}
+ (NSString *)allStates:(int)index;
+ (NSString *)abbreviatedState:(NSString *)strState;
@end
StateAbbreviation.m
@implementation StateAbbreviation
+ (NSString *)allStates:(NSString *)strState {
// Remove all space on the string
strState = [strState stringByReplacingOccurrencesOfString:@" " withString:@""];
//Sample states
NSArray *states = [[NSArray alloc] initWithObjects:
@"ALABAMA",
@"ALASKA", //AK
@"AMERICANSAMOA", //AS
@"ARIZONA", //AZ
@"ARKANSAS", //AR
@"CALIFORNIA", //CA
nil];
NSUInteger n = [states indexOfObject:strState];
if (n > [states count] - 1) {
strAbbreviation = @"NOSTATE";
}
else {
strAbbreviation =[self abbreviatedState:n];
}
[states release];
return strAbbreviation;
}
+ (NSString *)abbreviatedState:(int)index {
NSArray *states = [[NSArray alloc] initWithObjects:
@"AL",
@"AK",
@"AS",
@"AZ",
@"AR",
@"CA",
nil];
NSString *strAbbreviation = [states objectAtIndex:index];
[states release];
return strAbbreviation;
}
@end
当您调用该类时，应该像这样：
NSString *upperCase = [@"California" uppercaseString]; // California could be from (NSString *)placemark.administrativeArea;
NSString *abbr = [StateAbbreviation allStates:upperCase];
NSLog(@"%@", abbr); // Result should be CA
- DLende
3
1谢谢！但是你能更新一下代码，展示如何使用administrativeArea实现吗？我只需要把它放在类似于objectForKey的东西里面吗？我有点困惑怎么做。感谢你的回答！ - sridvijay
谢谢您的更新，但是我在做这个过程中出现了2个错误。 1. 在类方法中访问实例变量“strAbbreviation”。2. 在ARC中不允许将NSUInteger隐式转换为NSString *。我删掉了释放语句，以便在ARC中运行它，但我不知道如何解决这两个问题。再次感谢您的帮助，我非常感激。 - sridvijay
1没问题，不过你能帮我解决这个问题吗？:p - sridvijay
2
我认为这份文档有误。对于位于美国的地方，administrativeArea始终会返回完整的州名。要获取该州的缩写，您很可能需要创建一个字典查找表，以便搜索键“加利福尼亚”将返回值“CA”。
- George Clingerman
1
这是另一种使用FormattedAddressLines的类别，它返回类似于加利福尼亚州，CA的结果。
-(NSString *) stateWithAbbreviation {
if ([[self.addressDictionary objectForKey:@"CountryCode"] isEqualToString:@"US"] && self.addressDictionary) {
NSDictionary *addressLines = [self.addressDictionary objectForKey:@"FormattedAddressLines"];
for (NSString* addressLine in addressLines) {
NSRange stateRange = [addressLine rangeOfString:self.postalCode options:NSCaseInsensitiveSearch];
if (stateRange.length > 0) {
NSRange lastSpace = [addressLine rangeOfString:@" " options:NSBackwardsSearch];
if (lastSpace.length > 0) {
NSString *state = [[addressLine substringToIndex:lastSpace.location] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
lastSpace = [state rangeOfString:@" " options:NSBackwardsSearch];
if (lastSpace.length > 0) {
NSString *abbr = [[state substringFromIndex:lastSpace.location] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
return [NSString stringWithFormat:@"%@, %@", self.administrativeArea, abbr];
}
}
}
}
}
return self.administrativeArea;
}
只要苹果不改变地址行的格式，这个方法虽不完美但能够使用。
- xarux
1
对于需要将对象和键交换的州列表（例如在iOS 7上，我从placemark.administrativeArea中获取“CA”）的人：
NSDictionary *nameAbbreviations = [NSDictionary dictionaryWithObjectsAndKeys:
@"alabama",@"AL",
@"alaska",@"AK",
@"arizona",@"AZ",
@"arkansas",@"AR",
@"california",@"CA",
@"colorado",@"CO",
@"connecticut",@"CT",
@"delaware",@"DE",
@"district of columbia",@"DC",
@"florida",@"FL",
@"georgia",@"GA",
@"hawaii",@"HI",
@"idaho",@"ID",
@"illinois",@"IL",
@"indiana",@"IN",
@"iowa",@"IA",
@"kansas",@"KS",
@"kentucky",@"KY",
@"louisiana",@"LA",
@"maine",@"ME",
@"maryland",@"MD",
@"massachusetts",@"MA",
@"michigan",@"MI",
@"minnesota",@"MN",
@"mississippi",@"MS",
@"missouri",@"MO",
@"montana",@"MT",
@"nebraska",@"NE",
@"nevada",@"NV",
@"new hampshire",@"NH",
@"new jersey",@"NJ",
@"new mexico",@"NM",
@"new york",@"NY",
@"north carolina",@"NC",
@"north dakota",@"ND",
@"ohio",@"OH",
@"oklahoma",@"OK",
@"oregon",@"OR",
@"pennsylvania",@"PA",
@"rhode island",@"RI",
@"south carolina",@"SC",
@"south dakota",@"SD",
@"tennessee",@"TN",
@"texas",@"TX",
@"utah",@"UT",
@"vermont",@"VT",
@"virginia",@"VA",
@"washington",@"WA",
@"west virginia",@"WV",
@"wisconsin",@"WI",
@"wyoming",@"WY",
nil];
- John Erck
0
从至少iOS 8开始，CLPlacemark的administrativeArea返回美国州的两个字母缩写。
只要你的目标是iOS 8及更高版本（现在应该是这样），就不需要像接受的答案中那样使用类别扩展CLPlacemark。
CLGeocoder *geocoder = [[CLGeocoder alloc] init];
[geocoder geocodeAddressString:@"1 Infinite Loop, Cupertino, CA" completionHandler:^(NSArray *placemarks, NSError *error) {
CLPlacemark *placemark = [placemarks firstObject];
NSLog(@"State: %@", placemark.administrativeArea);
}];
运行此代码，你将会得到：
State: CA
- T Blank
1
1根据苹果最新提供的文档，这并不是一个正确的陈述：
该属性中的字符串可以是行政区域的全称，也可以是其指定的缩写（如果存在）。例如，如果地标位置是苹果公司总部，则此属性的值将为字符串“CA”或“California”。 - Mark T.
0
字典的 SWIFT 变体
let states = [
"AL":"alabama",
"AK":"alaska",
"AZ":"arizona",
"AR":"arkansas",
"CA":"california",
"CO":"colorado",
"CT":"connecticut",
"DE":"delaware",
"DC":"district of columbia",
"FL":"florida",
"GA":"georgia",
"HI":"hawaii",
"ID":"idaho",
"IL":"illinois",
"IN":"indiana",
"IA":"iowa",
"KS":"kansas",
"KY":"kentucky",
"LA":"louisiana",
"ME":"maine",
"MD":"maryland",
"MA":"massachusetts",
"MI":"michigan",
"MN":"minnesota",
"MS":"mississippi",
"MO":"missouri",
"MT":"montana",
"NE":"nebraska",
"NV":"nevada",
"NH":"new hampshire",
"NJ":"new jersey",
"NM":"new mexico",
"NY":"new york",
"NC":"north carolina",
"ND":"north dakota",
"OH":"ohio",
"OK":"oklahoma",
"OR":"oregon",
"PA":"pennsylvania",
"RI":"rhode island",
"SC":"south carolina",
"SD":"south dakota",
"TN":"tennessee",
"TX":"texas",
"UT":"utah",
"VT":"vermont",
"VA":"virginia",
"WA":"washington",
"WV":"west virginia",
"WI":"wisconsin",
"WY":"wyoming"
]
- Олексій Безродний
网页内容由stack overflow 提供, 点击上面的可以查看英文原文，
原文链接
原文链接
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