我正在使用基于GnuCOBOL的OpenCobolIDE 4.7.4,在Windows 10上尝试编译这个程序以打开一个读取文件:
IDENTIFICATION DIVISION.
PROGRAM-ID. HELLO.
ENVIRONMENT DIVISION.
INPUT-OUTPUT SECTION.
FILE-CONTROL.
SELECT STUDENT ASSIGN TO 'input.txt'
ORGANIZATION IS LINE SEQUENTIAL.
DATA DIVISION.
FILE SECTION.
FD STUDENT.
01 STUDENT-FILE.
05 STUDENT-ID PIC 9(5).
05 NAME PIC A(25).
WORKING-STORAGE SECTION.
01 WS-STUDENT.
05 WS-STUDENT-ID PIC 9(5).
05 WS-NAME PIC A(25).
01 WS-EOF PIC A(1).
PROCEDURE DIVISION.
OPEN INPUT STUDENT.
PERFORM UNTIL WS-EOF='Y'
READ STUDENT INTO WS-STUDENT
AT END MOVE 'Y' TO WS-EOF
NOT AT END DISPLAY WS-STUDENT
END-READ
END-PERFORM.
CLOSE STUDENT.
STOP RUN.
< p > input.txt 与源代码在同一目录中,但我仍然遇到以下错误:
Main.cob:24: libcob: File does not exist (STATUS = 35) File : 'input.txt'
我做错了什么?