红色
和蓝色
只是您图像的视图。当您执行img[:,:,0] = red
时,这会更改img
,但也会更改blue
,因为它只是一个视图(基本上只是对子数组img[:,:,0]
的引用),而不是副本,因此您会丢失原始的蓝色通道值。基本上您认为是一个临时副本实际上并不是。添加.copy()
即可解决问题。
img = np.arange(27).reshape((3,3,3))
red = img[:,:,2].copy()
blue = img[:,:,0].copy()
img[:,:,0] = red
img[:,:,2] = blue
print("with copy:\n", img)
img = np.arange(27).reshape((3,3,3))
red = img[:,:,2]
blue = img[:,:,0]
img[:,:,0] = red
img[:,:,2] = blue
print("without copy:\n",img)
结果:
带有复制文本:
[[[ 2 1 0]
[ 5 4 3]
[ 8 7 6]]
[[11 10 9]
[14 13 12]
[17 16 15]]
[[20 19 18]
[23 22 21]
[26 25 24]]]
没有复制:
[[[ 2 1 2]
[ 5 4 5]
[ 8 7 8]]
[[11 10 11]
[14 13 14]
[17 16 17]]
[[20 19 20]
[23 22 23]
[26 25 26]]]
注意:实际上你只需要一个临时副本来存储一个通道。或者你可以简单地执行img[:,:,::-1]
,这将创建一个视图,但通道会被交换,img
将保持不变,除非你重新赋值它:
img = np.arange(27).reshape((3,3,3))
print(img[:,:,::-1])
print(img)
img = img[:,:,::-1]
print(img)
结果:
[[[ 2 1 0]
[ 5 4 3]
[ 8 7 6]]
[[11 10 9]
[14 13 12]
[17 16 15]]
[[20 19 18]
[23 22 21]
[26 25 24]]]
[[[ 0 1 2]
[ 3 4 5]
[ 6 7 8]]
[[ 9 10 11]
[12 13 14]
[15 16 17]]
[[18 19 20]
[21 22 23]
[24 25 26]]]
[[[ 2 1 0]
[ 5 4 3]
[ 8 7 6]]
[[11 10 9]
[14 13 12]
[17 16 15]]
[[20 19 18]
[23 22 21]
[26 25 24]]]