我遇到了一个有趣的问题。由于某种原因,serde无法从字符串中反序列化出与已序列化的
这里是程序演示链接:playground link 输出结果如下:
chrono::DateTime<Utc>
对象相同格式的内容(但如果我保存了包含该对象的变量,则可以解析成功)。use chrono; // 0.4.11
use serde_json; // 1.0.48
fn main() {
let date = chrono::Utc::now();
println!("{}", date);
let date_str = serde_json::to_string(&date).unwrap();
println!("{}", date_str);
let parsed_date: chrono::DateTime<chrono::Utc> = serde_json::from_str(&date_str).unwrap();
println!("{}", parsed_date);
assert_eq!(date, parsed_date);
let date = "2020-03-28T16:29:04.644008111Z";
let _: chrono::DateTime<chrono::Utc> = serde_json::from_str(&date).unwrap();
}
这里是程序演示链接:playground link 输出结果如下:
Compiling playground v0.0.1 (/playground)
Finished dev [unoptimized + debuginfo] target(s) in 1.01s
Running `target/debug/playground`
thread 'main' panicked at 'called `Result::unwrap()` on an `Err` value: Error("invalid type: integer `2020`, expected a formatted date and time string or a unix timestamp", line: 1, column: 4)', src/main.rs:17:44
note: run with `RUST_BACKTRACE=1` environment variable to display a backtrace
Standard Output
2020-03-28 17:57:04.222452521 UTC
"2020-03-28T17:57:04.222452521Z"
2020-03-28 17:57:04.222452521 UTC
为什么会发生这种情况?我应该如何处理?