Classic Asp中返回对象

4

我正在使用经典的Asp来构建请求到一个Url,现在成功了,但问题是我想从函数中返回请求对象,而且出现了以下问题:对象不支持此属性或方法,我该怎么办?

Set objSrvHTTP = Server.CreateObject ("Msxml2.ServerXMLHTTP.3.0")
objSrvHTTP.open "POST","Https://",False,"",""
objSrvHTTP.SetRequestHeader "Content-Type", "text/xml"
objSrvHTTP.SetRequestHeader "Authorization", "Basic " & EncodeBase64("sales@nutritionexpress.co.uk:f00tball")
objSrvHTTP.SetRequestHeader "dev-t", " MyAccessKey "
objSrvHTTP.SetRequestHeader "Cookie", "ubid-main=172-9288630-2514702; session-id=026-6553457-3334020; session-id-time=1191279600l;"
objSrvHTTP.send
BuildRequest=objSrvHTTP

谢谢

1个回答

13

更改

BuildRequest=objSrvHTTP  

Set BuildRequest=objSrvHTTP

返回该对象。


网页内容由stack overflow 提供, 点击上面的
可以查看英文原文,
原文链接