我有一个像这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
我怎么能将它转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
我有一个像这样的字符串:
abc=foo&def=%5Basf%5D&xyz=5
我怎么能将它转换为这样的JavaScript对象?
{
abc: 'foo',
def: '[asf]',
xyz: 5
}
console.log(decodeURI('abc=foo&def=%5Basf%5D&xyz=5')
.split('&')
.reduce((result, current) => {
const [key, value] = current.split('=');
result[key] = value;
return result
}, {}))
YouAreI = require('YouAreI')
uri = new YouAreI('http://user:pass@www.example.com:3000/a/b/c?d=dad&e=1&f=12.3#fragment');
uri.query_get() => { d: 'dad', e: '1', f: '12.3' }
var result = URI.parseQuery("?foo=bar&hello=world&hello=mars&bam=&yup");
result === {
foo: "bar",
hello: ["world", "mars"],
bam: "",
yup: null
};
npm i js-extension-ling
const jsx = require("js-extension-ling");
console.log(jsx.queryStringToObject("a=1"));
console.log(jsx.queryStringToObject("a=1&a=3"));
console.log(jsx.queryStringToObject("a[]=1"));
console.log(jsx.queryStringToObject("a[]=1&a[]=pomme"));
console.log(jsx.queryStringToObject("a[0]=one&a[1]=five"));
console.log(jsx.queryStringToObject("http://blabla?foo=bar&number=1234"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry"));
console.log(jsx.queryStringToObject("a[fruits][red][]=strawberry&a[1]=five&a[fruits][red][]=cherry&a[fruits][yellow][]=lemon&a[fruits][yellow][688]=banana"));
{ a: '1' }
{ a: '3' }
{ a: { '0': '1' } }
{ a: { '0': '1', '1': 'pomme' } }
{ a: { '0': 'one', '1': 'five' } }
{ foo: 'bar', number: '1234' }
{
a: { fruits: { red: { '0': 'strawberry' } } }
}
{
a: {
'1': 'five',
fruits: {
red: { '0': 'strawberry', '1': 'cherry' },
yellow: { '0': 'lemon', '688': 'banana' }
}
}
}
var params = {};
window.location.search.substring(1).split('&').forEach(function(pair) {
pair = pair.split('=');
if (pair[1] !== undefined) {
var key = decodeURIComponent(pair[0]),
val = decodeURIComponent(pair[1]),
val = val ? val.replace(/\++/g,' ').trim() : '';
if (key.length === 0) {
return;
}
if (params[key] === undefined) {
params[key] = val;
}
else {
if ("function" !== typeof params[key].push) {
params[key] = [params[key]];
}
params[key].push(val);
}
}
});
console.log(params);
基本用法,例如:
?a=aa&b=bb
Object {a: "aa", b: "bb"}
重复参数,例如:
?a=aa&b=bb&c=cc&c=potato
Object {a: "aa", b: "bb", c: ["cc","potato"]}
缺失键名,例如:
?a=aa&b=bb&=cc
Object {a: "aa", b: "bb"}
缺失键值,例如:
?a=aa&b=bb&c
Object {a: "aa", b: "bb"}
上述 JSON/正则表达式解决方案在以下奇怪的 URL 上会抛出语法错误:
?a=aa&b=bb&c=&=dd&e
Object {a: "aa", b: "bb", c: ""}
//under ES6
const getUrlParamAsObject = (url = window.location.href) => {
let searchParams = url.split('?')[1];
const result = {};
//in case the queryString is empty
if (searchParams!==undefined) {
const paramParts = searchParams.split('&');
for(let part of paramParts) {
let paramValuePair = part.split('=');
//exclude the case when the param has no value
if(paramValuePair.length===2) {
result[paramValuePair[0]] = decodeURIComponent(paramValuePair[1]);
}
}
}
return result;
}
Babel
的帮助,@Scribblemacher 可以在其他环境下很好地完成它。 - XYz Amos function paramsToJSON(str) {
var pairs = str.split('&');
var result = {};
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = pair[0]
var value = pair[1]
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result );
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
paramsToJSON("x=1&x=2&x=3&y=blah");
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
后来我决定将其转换为jQuery插件...
$.fn.serializeURLParams = function() {
var result = {};
if( !this.is("a") || this.attr("href").indexOf("?") == -1 )
return( result );
var pairs = this.attr("href").split("?")[1].split('&');
pairs.forEach(function(pair) {
pair = pair.split('=');
var name = decodeURI(pair[0])
var value = decodeURI(pair[1])
if( name.length )
if (result[name] !== undefined) {
if (!result[name].push) {
result[name] = [result[name]];
}
result[name].push(value || '');
} else {
result[name] = value || '';
}
});
return( result )
}
<a href="index.html?x=1&x=2&x=3&y=blah">something</a>
$("a").serializeURLParams();
console yields => {x: Array[3], y: "blah"} where x is an array as is proper JSON
function deparam(paramStr) {
let paramArr = paramStr.split('&');
let paramObj = {};
paramArr.forEach(e=>{
let param = e.split('=');
paramObj[param[0]] = decodeURIComponent(param[1]);
});
return paramObj;
}
deparam('abc=foo&def=%5Basf%5D&xyz=5')
{
abc: "foo"
def:"[asf]"
xyz :"5"
}
这里是silicakes' approach的更简化版本。
以下函数可以从USVString
或Location
中解析查询字符串。
/**
* Returns a plain object representation of a URLSearchParams object.
* @param {USVString} search - A URL querystring
* @return {Object} a key-value pair object from a URL querystring
*/
const parseSearch = (search) =>
[...new URLSearchParams(search).entries()]
.reduce((acc, [key, val]) => ({
...acc,
// eslint-disable-next-line no-nested-ternary
[key]: Object.prototype.hasOwnProperty.call(acc, key)
? Array.isArray(acc[key])
? [...acc[key], val]
: [acc[key], val]
: val
}), {});
/**
* Returns a plain object representation of a URLSearchParams object.
* @param {Location} location - Either a document or window location, or React useLocation()
* @return {Object} a key-value pair object from a URL querystring
*/
const parseLocationSearch = (location) => parseSearch(location.search);
console.log(parseSearch('?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D'));
.as-console-wrapper { top: 0; max-height: 100% !important; }
其中
f
是parseSearch
f=s=>[...new URLSearchParams(s).entries()].reduce((a,[k,v])=>({...a,[k]:a[k]?Array.isArray(a[k])?[...a[k],v]:[a[k],v]:v}),{})
这里介绍一种序列化和更新的方法:
const parseSearch = (search) =>
[...new URLSearchParams(search).entries()]
.reduce((acc, [key, val]) => ({
...acc,
// eslint-disable-next-line no-nested-ternary
[key]: Object.prototype.hasOwnProperty.call(acc, key)
? Array.isArray(acc[key])
? [...acc[key], val]
: [acc[key], val]
: val
}), {});
const toQueryString = (params) =>
`?${Object.entries(params)
.flatMap(([key, values]) =>
Array.isArray(values)
? values.map(value => [key, value])
: [[key, values]])
.map(pair => pair.map(val => encodeURIComponent(val)).join('='))
.join('&')}`;
const updateQueryString = (search, update) =>
(parsed =>
toQueryString(update instanceof Function
? update(parsed)
: { ...parsed, ...update }))
(parseSearch(search));
const queryString = '?foo=bar&x=y&ids=%5B1%2C2%2C3%5D&ids=%5B4%2C5%2C6%5D';
const parsedQuery = parseSearch(queryString);
console.log(parsedQuery);
console.log(toQueryString(parsedQuery) === queryString);
const updatedQuerySimple = updateQueryString(queryString, {
foo: 'baz',
x: 'z',
});
console.log(updatedQuerySimple);
console.log(parseSearch(updatedQuerySimple));
const updatedQuery = updateQueryString(updatedQuerySimple, parsed => ({
...parsed,
ids: [
...parsed.ids,
JSON.stringify([7,8,9])
]
}));
console.log(updatedQuery);
console.log(parseSearch(updatedQuery));
.as-console-wrapper { top: 0; max-height: 100% !important; }
我需要处理URL的查询部分中的+
号(decodeURIComponent不支持),因此我改编了Wolfgang的代码如下:
var search = location.search.substring(1);
search = search?JSON.parse('{"' + search.replace(/\+/g, ' ').replace(/&/g, '","').replace(/=/g,'":"') + '"}',
function(key, value) { return key===""?value:decodeURIComponent(value)}):{};
var objForm = JSON.parse('{"' + $myForm.serialize().replace(/\+/g, ' ').replace(/&/g, '","').replace(/=/g,'":"') + '"}',
function(key, value) { return key===""?value:decodeURIComponent(value)});
objForm.anyParam += stringToAddToTheParam;
var serializedForm = $.param(objForm);