use WWW::Curl::Easy 4.14;
use WWW::Curl::Form;
my $url = 'http://example.com/backups/?sid=12313qwed323';
my $params = {
name => 'upload',
action => 'keep',
backup1 => [ '/tmp/backup1.zip' ], # 1st file for upload
};
my $form = WWW::Curl::Form->new();
foreach my $k (keys %{$params}) {
if (ref $params->{$k}) {
$form->formaddfile(@{$params->{$k}}[0], $k, 'multipart/form-data');
} else {
$form->formadd($k, $params->{$k});
}
}
my $curl = WWW::Curl::Easy->new() or die $!;
$curl->setopt(CURLOPT_HTTPPOST, $form);
$curl->setopt(CURLOPT_URL, $url);
my $body;
$curl->setopt(CURLOPT_WRITEDATA, \$body);
my $retcode = $curl->perform();
my $response_code = $curl->getinfo(CURLINFO_HTTP_CODE);
这里没有什么特别的,代码可以正常工作。
我想上传大文件,但不想将所有内容预加载到内存中。至少我听说libcurl正在做这件事。
CURLOPT_READFUNCTION接受回调函数,返回内容的部分。这意味着我无法使用WWW::Curl::Form设置POST参数,而是必须通过此回调函数返回整个内容。是这样吗?
我认为代码可能如下所示:
use WWW::Curl::Easy 4.14;
my $url = 'http://example.com/backups/?sid=12313qwed323'
my $params = {
name => 'upload',
action => 'keep',
backup1 => [ '/tmp/backup1.zip' ], # 1st file for upload
};
my $fields;
foreach my $k (keys %{$params}) {
$fields .= "$k=".(ref $params->{$k} ? '@'.@{$params->{$k}}[0] : uri_escape_utf8($params->{$k}))."&";
}
chop($fields);
my $curl = WWW::Curl::Easy->new() or die $!;
$curl->setopt(CURLOPT_POST, 1);
$curl->setopt(CURLOPT_POSTFIELDS, $fields); # is it needed with READFUNCTION??
$curl->setopt(CURLOPT_URL, $url);
my @header = ('Content-type: multipart/form-data', 'Transfer-Encoding: chunked');
$curl->setopt(CURLOPT_HTTPHEADER, \@header);
#$curl->setopt(CURLOPT_INFILESIZE, $size);
$curl->setopt(CURLOPT_READFUNCTION, sub {
# which data to return here?
# $params (without file) + file content?
return 0;
});
CURLOPT_READFUNCTION回调函数需要返回哪些数据?$params和文件内容?它们应该是哪种格式?
我真的需要自己创建由CURLOPT_READFUNCTION返回的数据吗?还是有简单的方法可以创建正确格式的数据?
谢谢。