重复执行for循环的迭代

Question

如果出于某种原因我想要重复相同的迭代，我该如何在Python中实现？

for eachId in listOfIds:
    #assume here that eachId conatins 10
    response = makeRequest(eachId) #assume that makeRequest function request to a url by using this id
    if response == 'market is closed':
       time.sleep(24*60*60) #sleep for one day

现在当函数从睡眠中醒来一天后（市场（货币交易市场）开放），我想从eachId = 10继续我的for循环，而不是从eachId = 11开始，因为eachId = 10还没有像市场已关闭一样被处理，非常感谢任何帮助。

- Aamir Rind

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save the content into a list. - JBernardo

他的意思是如何在某次迭代中不增加For循环的列表计数器。 - bcoughlan

Answer 1

按照以下方式处理：

for eachId in listOfIds:
    successful = False
    while not successful:        
        response = makeRequest(eachId)
        if response == 'market is closed':
            time.sleep(24*60*60) #sleep for one day
        else:
            successful = True

你的问题标题就是线索。通过迭代可以实现重复，在这种情况下，你可以简单地使用嵌套的while来完成。

- David Heffernan

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感谢您的帮助，嵌套 while 循环，啊啊啊，为什么我没想到呢 :p - Aamir Rind

Answer 2

使用 while 循环吗？

counter = 0
while counter < len(listOfIds):
  # do processing
  counter = counter + 1

如果你收到“市场已关闭”的消息，就不要增加。

- Geo

Answer 3

i = 0
while i < len(listOfIds):
    eachId = listOfIds[i]
    #assume here that eachId conatins 10
    response = makeRequest(eachId) #assume that makeRequest function request to a url by using this id
    if response == 'market is closed':
       time.sleep(24*60*60) #sleep for one day
    else:
       i += 1

- etuardu

Answer 4

for eachId in listOfIds:
    while makeRequest(eachId) == 'market is closed':
       time.sleep(24*60*60) #sleep for one day

正如 @David 所添加的，如果您不需要捕获 response。

- eph

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除非需要捕获“响应(response)”，否则必须尽可能简洁。 - David Heffernan