从字符串中删除多个单词的更好方法是什么？

Question

bannedWord = ["Good", "Bad", "Ugly"]
    
def RemoveBannedWords(toPrint, database):
    statement = toPrint
    for x in range(0, len(database)):
        if bannedWord[x] in statement:
            statement = statement.replace(bannedWord[x] + " ", "")
    return statement
        
toPrint = "Hello Ugly Guy, Good To See You."
    
print(RemoveBannedWords(toPrint, bannedWord))

输出结果为Hello Guy, To See You.，我认为使用Python有更好的方法来实现在字符串中更改多个单词。我搜索了一些使用字典的类似解决方案，但似乎并不适合这种情况。

- Andy Wong

Answer 1

我使用

bannedWord = ['Good','Bad','Ugly']
toPrint = 'Hello Ugly Guy, Good To See You.'
print(' '.join(i for i in toPrint.split() if i not in bannedWord))

- Shreevardhan

Answer 2

这里有一个使用正则表达式的解决方案：

import re
    
def RemoveBannedWords(toPrint,database):
    statement = toPrint
    pattern = re.compile("\\b(Good|Bad|Ugly)\\W", re.I)
    return pattern.sub("", toPrint)
    
toPrint = "Hello Ugly Guy, Good To See You."
    
print(RemoveBannedWords(toPrint,bannedWord))

- Ajay Gupta

Answer 3

在Ajay的代码上稍作修改，当禁用单词列表中的一个字符串为另一个字符串的子串时。

bannedWord = ['good', 'bad', 'good guy' 'ugly']

toPrint ='good winter good guy'的结果将是：

RemoveBannedWords(toPrint,database = bannedWord) = 'winter good'

因为它先移除good。需要根据列表中元素的长度进行排序。

import re

def RemoveBannedWords(toPrint,database):
    statement = toPrint
    database_1 = sorted(list(database), key=len)
    pattern = re.compile(r"\b(" + "|".join(database_1) + ")\\W", re.I)
    return pattern.sub("", toPrint + ' ')[:-1] #added because it skipped last word

toPrint = 'good winter good guy.'

print(RemoveBannedWords(toPrint,bannedWord))

- Itachi

Answer 4

又是一个主题的变体。如果你要经常调用它，那么最好编译一次正则表达式以提高速度:

import re

bannedWord = ['Good', 'Bad', 'Ugly']
re_banned_words = re.compile(r"\b(" + "|".join(bannedWord) + ")\\W", re.I)

def RemoveBannedWords(toPrint):
    global re_banned_words
    return re_banned_words.sub("", toPrint)

toPrint = 'Hello Ugly Guy, Good To See You.'
print(RemoveBannedWords(toPrint))

- Martin Evans

---

最佳答案，很奇怪为什么只有这么少的投票。如果你需要找到嵌入的词，请在 \\W 后面添加星号“*”：re.compile(r"\b(" + "|".join(list_not_for_search) + ")\\W*", re.I)，例如在“Hello uglyyy guy, good to see you.”中将排除“ugly”，并输出“yy”作为其余部分。顺便说一下：re.I 代表 re.IGNORECASE。 - questionto42

Answer 5

由于您正在检查开头的单词边界和结尾处的非单词字符，因此正则表达式是首选。 仍然可以使用内存中的数组/列表

bannedWord = ['Good', 'Bad', 'Ugly']

toPrint = 'Hello Uglyyy Guy, Good To See You.'

for word in bannedWord:
    toPrint = toPrint.replace(word, "")

print(toPrint) 

Hello yy Guy,  To See You.

[Program finished] 

- Subham