请帮我将以下C++代码转换为ctypes Python:
Ret = openFcn(&Handle, "C:\\Config.xml");
以下是每个声明的内容:
typedef uint16_t (* OpenDLLFcnP)(void **, const char *);
OpenDLLFcnP openFcn = NULL;
openFcn = (OpenDLLFcnP) myLibrary.resolve("Open");
void *Handle = NULL;
请帮我将以下C++代码转换为ctypes Python:
Ret = openFcn(&Handle, "C:\\Config.xml");
typedef uint16_t (* OpenDLLFcnP)(void **, const char *);
OpenDLLFcnP openFcn = NULL;
openFcn = (OpenDLLFcnP) myLibrary.resolve("Open");
void *Handle = NULL;
myLibrary.resolve
未定义,但您需要的一般代码(未经测试)如下:
import ctypes
dll = ctypes.CDLL('your.dll')
Open = dll.Open
Open.argtypes = [ctypes.POINTER(ctypes.c_void_p),ctypes.c_char_p]
Open.restype = ctypes.c_uint16
Handle = ctypes.c_void_p()
result = Open(ctypes.byref(Handle),'c:\\Config.xml')
your.dll
的 DLL 文件,其中包含一个名为 Open
的函数需要调用。