如何基于ID筛选对象数组？

Question

我有一个对象数组，我想循环遍历它并根据传入函数的id或code进行过滤。请保留HTML标签。

state.products = [{id = 1, name = Bottle},{id = 2, name = umbrella}, {id = 3, name = shoe}]

const getVal = (id)=> {

 const av = state.products.filter((s) s.productId == id)

}

以下代码似乎没有遍历数组并检查每个对象？我在console.log（av）中得到一个空数组。

- Kashyap

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state.products.filter((s) => s.id == id) - Dhaval Marthak

Answer 1

你正在走正确的道路，但你没有正确使用 Array.filter。

此外，提供的对象数组格式也不够好。对象应该是 键：值对。

state.products = [
    { id: 1, name: "Bottle" },
    { id: 2, name: "umbrella" },
    { id: 3, name: "shoe" }
]

const getAllArrayExcept = (id) => {
    // this will return all the array except provided id
    return state.products.filter((s) => s.id !== id)
}

const getOnlyArray = (id) => {
    // this will return only item which match the provided id
    return state.products.filter((s) => s.id === id)
}

console.log(getAllArrayExcept(1))
/*
output: [{ id = 2, name = umbrella }, { id = 3, name = shoe }]
*/
console.log(getOnlyArray(1))
/*
output: [{ id = 1, name = Bottle }]
*/

这里是可用的代码片段：

const products = [
    { id: 1, name: "Bottle" },
    { id: 2, name: "umbrella" },
    { id: 3, name: "shoe" }
]

const getAllArrayExcept = (id) => {
    // this will return all the array except provided id
    return products.filter((s) => s.id !== id)
}

const getOnlyArray = (id) => {
    // this will return only item which match the provided id
    return products.filter((s) => s.id === id)
}

console.log("All array except: ", getAllArrayExcept(1))
console.log("Only provided item in array: ", getOnlyArray(1))

- Pradip Dhakal