这需要显式同步吗?

4

我有两个线程,并希望确保在LinkedBlockingQueue上正确进行同步。这个做法正确吗?或者对(messageToCommsQuueue)进行显式同步是不必要的吗?

声明:

    private LinkedBlockingQueue<BaseMessage> messagesToCommsQueue;

方法一:

private void startOperationModeStatusMessageExecutor() {

    ScheduledExecutorService operationModeStatusExecutor = Executors.newSingleThreadScheduledExecutor();
    operationModeStatusExecutor.scheduleAtFixedRate((new Runnable() {

        @Override
        public void run() {
            ModeStatusMessage commsOperateMsg;
                commsOperateMsg = MessageFactory.getModeStatusMessage(status.ordinal());
            synchronized (messagesToCommsQueue) {
                messagesToCommsQueue.add(commsOperateMsg);
            }
        }

    }), 0, 10, TimeUnit.SECONDS);
}

方法二:
    Executor commsSenderExecutor = Executors.newSingleThreadExecutor();
    commsSenderExecutor.execute(new Runnable() {

        @Override
        public void run() {
            while (getStatus().equals(ModeStatus.INITIATE) || getStatus().equals(ModeStatus.OPERATE)) {
                BaseMessage m = null;
                try {
                    synchronized (messagesToCommsQueue) {
                        m = messagesToCommsQueue.take();
                    }
                } catch (InterruptedException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }



            }
        }

    });
1个回答

5

是的,这并非必须。JavaDoc 表示:

BlockingQueue 实现是线程安全的。


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