我有一个日期范围参数,需要将其拆分为多个日期,并且每个日期的时间与该参数相同。
不确定 ADDTIME
的问题在哪里,也许我缺少一个转换?我可以将其转换为字符串并连接解决,但我认为应该更容易。
当前输出
selectDate time(@s_date) time(@e_date) addtime(date(a.selectDate), time(@s_date))
1 2016-09-03 08:00:00 16:00:00 08:00:00
2 2016-09-04 08:00:00 16:00:00 08:00:00
期望输出
selectDate time(@s_date) time(@e_date) addtime(date(a.selectDate), time(@s_date))
1 2016-09-03 08:00:00 16:00:00 2016-09-03 08:00:00
2 2016-09-04 08:00:00 16:00:00 2016-09-04 08:00:00
可能的解决方案:
CONCAT(DATE_FORMAT(a.selectDate, '%Y-%m-%d '),
DATE_FORMAT(@s_date, '%H:%i:%s')) as start_time,
这是我的一个重要查询
select a.selectDate,
time(@s_date),
time(@e_date),
addtime(date(a.selectDate), time(@s_date))
from (
select '1900-01-01' + INTERVAL (a.a + (10 * b.a) + (100 * c.a) + (1000 * d.a) + (10000 * e.a)) DAY as selectDate
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as d
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as e
) a
CROSS JOIN (SELECT @s_date := '2016-09-03 08:00:00', @e_date := '2016-09-04 16:00:00') par
WHERE selectDate BETWEEN date(@s_date)
AND date(@e_date)