是否有可能获取传递给函数的变量的原始变量名？例如：
foobar = "foo"
def func(var):
print var.origname
所以：
func(foobar)
返回：
>>foobar
编辑：
我只是想创建一个像这样的函数：
def log(soup):
f = open(varname+'.html', 'w')
print >>f, soup.prettify()
f.close()
...并且让函数从传递给它的变量名生成文件名。
如果不可能的话，我想我只能每次将变量和变量名作为字符串传递。
def get_caller_params():
# get the frame object for this function call
thisframe = inspect.currentframe()
# get the parent calling frames details
frames = inspect.getouterframes(thisframe)
# frame 0 is the frame of this function
# frame 1 is the frame of the caller function (the one we want to inspect)
# frame 2 is the frame of the code that calls the caller
caller_function_name = frames[1][3]
code_that_calls_caller = inspect.findsource(frames[2][0])[0]
# parse code to get nodes of abstract syntact tree of the call
nodes = ast.parse(''.join(code_that_calls_caller))
# find the node that calls the function
i_expr = -1
for (i, node) in enumerate(nodes.body):
if _node_is_our_function_call(node, caller_function_name):
i_expr = i
break
# line with the call start
idx_start = nodes.body[i_expr].lineno - 1
# line with the end of the call
if i_expr < len(nodes.body) - 1:
# next expression marks the end of the call
idx_end = nodes.body[i_expr + 1].lineno - 1
else:
# end of the source marks the end of the call
idx_end = len(code_that_calls_caller)
call_lines = code_that_calls_caller[idx_start:idx_end]
str_func_call = ''.join([line.strip() for line in call_lines])
str_call_params = str_func_call[str_func_call.find('(') + 1:-1]
params = [p.strip() for p in str_call_params.split(',')]
return params
def _node_is_our_function_call(node, our_function_name):
node_is_call = hasattr(node, 'value') and isinstance(node.value, ast.Call)
if not node_is_call:
return False
function_name_correct = hasattr(node.value.func, 'id') and node.value.func.id == our_function_name
return function_name_correct
def test(*par_values):
par_names = get_caller_params()
for name, val in zip(par_names, par_values):
print(name, val)
a = 1
b = 2
string = 'text'
test(a, b,
string
)
要获得所需的输出：
a 1
b 2
string text
par_name 为 None，例如 test("x", 1000) 应该打印出 None x 然后是 None 1000？ - tsorn由于您可以拥有多个具有相同内容的变量，因此不是传递变量（内容），而是通过字符串传递其名称并从调用者堆栈帧中的本地字典获取变量内容可能更安全（并且更简单）。
def displayvar(name):
import sys
return name+" = "+repr(sys._getframe(1).f_locals[name])
__name__属性。def time_it(func, *args, **kwargs):
start = perf_counter()
result = func(*args, **kwargs)
duration = perf_counter() - start
print(f'{func.__name__} ran in {duration * 1000}ms')
return result