在Django中是否有类似于“rake routes”的功能?

58
在Rails中,可以使用rake命令(http://guides.rubyonrails.org/routing.html)显示活动路由。
$ rake routes
          users GET  /users          {:controller=>"users", :action=>"index"}
formatted_users GET  /users.:format  {:controller=>"users", :action=>"index"}
                POST /users          {:controller=>"users", :action=>"create"}
                POST /users.:format  {:controller=>"users", :action=>"create"}

是否有类似的工具/命令适用于Django,可以显示URL模式、模式名称(如果有)以及与视图相关联的函数等信息?


另一个好方法是,如果您处于调试模式,可以输入类似 http://127.0.0.1:8000/1234 这样的虚假 URL,它将显示URL模式。 - tread
4个回答

90

5

An experiment ...

# appended to root urls.py

if __name__ == '__main__':

    from django.core.urlresolvers import RegexURLPattern, RegexURLResolver
    from django.utils.termcolors import colorize
    import os, sys

    sys.path.append(os.path.abspath('..'))
    os.environ['DJANGO_SETTINGS_MODULE'] = 'ialtr.settings'

    def traverse(url_patterns, prefix=''):
        for p in url_patterns:
            if isinstance(p, RegexURLPattern):
                composed = '%s%s' % (prefix, p.regex.pattern)
                composed = composed.replace('/^', '/')
                print colorize('\t%s' % (composed), fg='green'), '==> ',
                try:
                    sys.stdout.write(colorize('%s.' % p.callback.__module__,
                        fg='yellow'))
                    print p.callback.func_name
                except:
                    print p.callback.__class__.__name__
            if isinstance(p, RegexURLResolver):
                traverse(p.url_patterns, prefix=p.regex.pattern)

    traverse(urlpatterns)

现在,如果有人运行python urls.py...
$ python urls.py
    ^users/activate/complete/$ ==> django.views.generic.simple.direct_to_template
    ^users/activate/(?P<activation_key>\w+)/$ ==> registration.views.activate
    ^users/register/$ ==> registration.views.register
    ^users/register/complete/$ ==> django.views.generic.simple.direct_to_template
    ^users/register/closed/$ ==> django.views.generic.simple.direct_to_template
    ^login/$ ==> django.contrib.auth.views.MethodDecoratorAdaptor
    ^logout/$ ==> django.contrib.auth.views.logout
    ^password/change/$ ==> django.contrib.auth.views.MethodDecoratorAdaptor
    ^password/change/done/$ ==> django.contrib.auth.views.password_change_done
    ^password/reset/$ ==> django.contrib.auth.views.MethodDecoratorAdaptor
    ^password/reset/confirm/(?P<uidb36>[0-9A-Za-z]+)-(?P<token>.+)/$ ==> django.contrib.auth.views.password_reset_confirm
    ^password/reset/complete/$ ==> django.contrib.auth.views.password_reset_complete
    ^password/reset/done/$ ==> django.contrib.auth.views.password_reset_done
    ^ialt/applications/$ ==> ialt.views.applications
    ^static/(?P<path>.*)$ ==> django.views.static.serve
    ^$ ==> django.views.generic.simple.direct_to_template
    ^about/ ==> django.views.generic.simple.direct_to_template

4
当我尝试使用miku's answer时,出现了以下错误:
django.core.exceptions.AppRegistryNotReady: 应用程序尚未加载。
看起来问题是由于在我的urls.py中使用了django.contrib.admin.autodiscover(),所以我可以将其注释掉,或者在转储URL之前正确加载Django。当然,如果我想在映射中看到管理URL,我不能注释它们。
我找到的方法是创建一个自定义管理命令来转储URL。
# install this file in mysite/myapp/management/commands/urldump.py
from django.core.management.base import BaseCommand

from kive import urls


class Command(BaseCommand):
    help = "Dumps all URL's."

    def handle(self, *args, **options):
        self.show_urls(urls.urlpatterns)

    def show_urls(self, urllist, depth=0):
        for entry in urllist:
            print ' '.join(("  " * depth, entry.regex.pattern,
                            entry.callback and entry.callback.__module__ or '',
                            entry.callback and entry.callback.func_name or ''))
            if hasattr(entry, 'url_patterns'):
                self.show_urls(entry.url_patterns, depth + 1)

1

admindocs 有类似的功能,但它不会显示URL名称。


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