当双击事件发生时,如何防止单击事件触发

57

我正在处理DOM元素上的单击和双击事件。每个事件执行不同的命令,但是当双击该元素时,除了触发双击事件外,还会触发两次单击事件。有什么防止这种行为的最佳方法吗?

14个回答

0

您可以使用防抖函数来避免单击处理程序检测到双击/多次点击。

测试链接:https://jsfiddle.net/L3sajybp/

HTML

<div id='toDetect'>
Click or double-click me
</div>
<hr/>

<ol id='info'>
</ol>

JS

function debounce(func, wait, immediate) {
    let timeout;
    return function () {
        const context = this,
            args = arguments;
        const later = function () {
            timeout = null;
            if (!immediate) func.apply(context, args);
        };
        const callNow = immediate && !timeout;
        clearTimeout(timeout);
        timeout = setTimeout(later, wait);
        if (callNow) func.apply(context, args);
    };
}

function debounceSingleClickOnly(func, timeout = 500) {
   function eventHandler (event) {
        const { detail } = event;
      if (detail > 1) {
         console.log('no double click for you '+ func.name);
         console.log('');
         return;
      }
      
      func.apply(this, arguments);
   }
   
   return debounce(eventHandler, timeout); 
}

window.toDetect.addEventListener('click', debounceSingleClickOnly(handleSingleClick));

window.toDetect.addEventListener('dblclick', handleDoubleClick);

function handleS() {
    console.log('S func');
  console.log(this.id);
}

function handleSingleClick(event) { 
   console.log('single click');
   const divText = document.createElement('li');
   divText.appendChild(document.createTextNode('single click'));
   window.info.appendChild(divText)

   console.group();
   console.log('this element was single-clicked: ' + event.target.id);   
   console.log(this.id);  
     console.log('');   
   console.groupEnd();
}

function handleDoubleClick(event) {
   console.log('double click');
   const divText = document.createElement('li');
   divText.appendChild(document.createTextNode('double click'));
   window.info.appendChild(divText);


     console.group();  
   console.log('this element was double-clicked: ' + event.target.id);
   console.log(this.id);  
     console.log('');
   console.groupEnd();
 }

输出:在此输入图像描述


这里只有一个最佳答案,却没有任何投票 :( - user13944038

0

这是我防止第二次点击的简单解决方案。当然,如果检测到双击,我可以重新启动超时,但实际上我从来不需要它。

clickTimeoutId = null;

onClick(e) {
    if (clickTimeoutId !== null) {
        // Double click, do nothing
        return;
    }

    // Single click
    // TODO smth

    clickTimeoutId = setTimeout(() => {
        clearTimeout(clickTimeoutId);
        clickTimeoutId = null;
    }, 300);
}

0
总结一下,要在同一个元素上识别simpleClick和doubleClick事件,只需使用以下方法处理onClick事件:
var EVENT_DOUBLE_CLICK_DELAY = 220; // Adjust max delay btw two clicks (ms)
var eventClickPending = 0;

function onClick(e){
    if ((e.detail == 2 ) && (eventClickPending!= 0)) {
//       console.log('double click action here ' + e.detail);
         clearTimeout(eventClickPending);
         eventClickPending = 0;
         // call your double click method
         fncEventDblclick(e);

    } else if ((e.detail === 1 ) && (eventClickPending== 0)){   
//      console.log('sigle click action here 1');
        eventClickPending= setTimeout(function() {
//          console.log('Executing sigle click');
            eventClickPending = 0
            // call your single click method
            fncEventClick(e);
        }, EVENT_DOUBLE_CLICK_DELAY);

//    } else { // do nothing
//      console.log('more than two clicks action here ' + e.detail);
            
    }
}

-1

  const toggle = () => {
      watchDouble += 1;
      setTimeout(()=>{
        if (watchDouble === 2) {
          console.log('double' + watchDouble)
        } else if (watchDouble === 1) {
          console.log("signle" + watchDouble)
        }
        watchDouble = 0
      },200);

  }

1
虽然这段代码片段可能解决了问题,但包括解释真的有助于提高您的帖子质量。请记住,您正在为未来的读者回答问题,而这些人可能不知道您的代码建议原因。 - Austen Holland

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