我正在创建一个Kotlin多平台库;实际上我有3个模块(common、jvm和js)。
在类路径中,我有:
- common:
但是当我运行这个简单的测试时:
在类路径中,我有:
classpath "org.jetbrains.kotlin:kotlin-serialization:${versions.kotlin}"
而在我的模块中,我有:- common:
"org.jetbrains.kotlinx:kotlinx-serialization-runtime-common:${versions.kotlinSerialization}"
- jdk: "org.jetbrains.kotlinx:kotlinx-serialization-runtime:${versions.kotlinSerialization}"
- js: "org.jetbrains.kotlinx:kotlinx-serialization-runtime-js:${versions.kotlinSerialization}"
当然还有apply plugin: 'kotlinx-serialization'
。但是当我运行这个简单的测试时:
@Serializable
data class ASimpleClass( val a: Int )
.
@Test
fun testingMultiplatformCode_canSerialize() {
JSON.stringify( ASimpleClass( 1 ) )
}
我遇到了这个错误:
kotlinx.serialization.SerializationException: Can't locate argument-less serializer for class studio.forface.ktmdb.ASimpleClass. For generic classes, such as lists, please provide serializer explicitly.
at kotlinx.serialization.PlatformUtilsKt.serializer(PlatformUtils.kt:28)
at studio.forface.ktmdb.ProjectTests.testingMultiplatformCode_canSerialize(ProjectTests.kt:33)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.junit.runner.JUnitCore.run(JUnitCore.java:137)
at com.intellij.junit4.JUnit4IdeaTestRunner.startRunnerWithArgs(JUnit4IdeaTestRunner.java:68)
at com.intellij.rt.execution.junit.IdeaTestRunner$Repeater.startRunnerWithArgs(IdeaTestRunner.java:47)
at com.intellij.rt.execution.junit.JUnitStarter.prepareStreamsAndStart(JUnitStarter.java:242)
at com.intellij.rt.execution.junit.JUnitStarter.main(JUnitStarter.java:70)
我在注释属性"a" (@SerialName
) 时得到了相同的结果,但这本来不需要注释。
我错过了什么吗? :/ 谢谢
无法找到类 studio.forface.ktmdb.ASimpleClass 的无参数序列化程序。
因此,也许您需要为该类提供一个无参数构造函数?只是猜测... - Thomas Cookkotlinx.serialization
库中的某些注解来注释属性a
...我猜测,由于a
没有被注释,序列化程序正在寻找一个无参数构造函数,但实际上并没有这样的构造函数,所以程序出现了错误... - Thomas Cook