如何在Windows Phone 7上将JSON解析为动态对象？

Question

对于 Web 应用程序，我可以使用 System.Web 并使用这个技巧 将 JSON 转换为动态对象。

但是对于 Windows Phone，我无法使用 JavaScriptConverter。有什么解决方案可以在 Windows Phone 7.1 上将 JSON 转换为动态对象吗？

- BrunoLM

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你所说的动态是指.NET4中的ExpandoObject吗？我认为WP7更接近于.NET35而不是.NET4，因此可能没有ExpandoObject。 - Just another metaprogrammer

@FuleSnabel 噢..你说得对...我可以在代码的某些部分使用dynamic编译，但我不能使用ExpandoObject...我猜我会把这个问题留着，或许有一天会有新的解决方法出现... - BrunoLM

你可以随时反序列化为字典。 - Just another metaprogrammer

请查看以下链接： https://dev59.com/d2oy5IYBdhLWcg3wKq0S - kai chen

检查一下这个获取工作：https://dev59.com/d2oy5IYBdhLWcg3wKq0S - kai chen

Answer 1

Json.Net ( http://james.newtonking.com/pages/json-net.aspx )

-----EDIT-----

If WP7 supports DynamicObject:

using System;
using System.Dynamic;
using System.Collections;

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

public class JSonTest 
{
    public static void Main()
    {
        string jsonStr = @"
            { 
                'glossary': { 
                    'title': 'example glossary', 
                    'GlossDiv': { 
                        'title': 'S', 
                        'GlossList': { 
                            'GlossEntry': { 
                                'ID': 'SGML', 
                                'SortAs': 'SGML', 
                                'GlossTerm': 'Standard Generalized Markup Language', 
                                'Acronym': 'SGML', 
                                'Abbrev': 'ISO 8879:1986', 
                                'GlossDef': { 
                                    'para': 'A meta-markup language, used to create markup languages such as DocBook.', 
                                    'GlossSeeAlso': ['GML','XML'] 
                                }, 
                                'GlossSee': 'markup' 
                            } 
                        } 
                    } 
                } 
            }
        ";

        JObject o = (JObject)JsonConvert.DeserializeObject(jsonStr);
        dynamic json = new JsonObject(o);
        Console.WriteLine(json.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.GlossSeeAlso.Length);
        Console.WriteLine(json.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.GlossSeeAlso[1]);
        foreach (var x in json.glossary.GlossDiv.GlossList.GlossEntry.GlossDef.GlossSeeAlso)
        {
            Console.WriteLine(x);
        }
        Console.ReadLine();
    }
}

class JsonObject : DynamicObject,IEnumerable,IEnumerator
{
    object _object;

    public JsonObject(object jObject)
    {
        this._object = jObject;
    }

    public object this[int i]
    {
        get
        {
            if (!(_object is JArray)) return null;

            object obj = (_object as JArray)[i];
            if (obj is JValue)
            {
                return ((JValue)obj).ToString();
            }
            return new JsonObject(obj);
        }
    }

    public override bool TryGetMember(GetMemberBinder binder, out object result)
    {
        result = null;

        if (_object is JArray && binder.Name == "Length")
        {
            result = (_object as JArray).Count;
            return true;
        }

        JObject jObject = _object as JObject;
        object obj = jObject.SelectToken(binder.Name);

        if (obj is JValue)
            result = ((JValue)obj).ToString();
        else
            result = new JsonObject(jObject.SelectToken(binder.Name));

        return true;
    }

    public override string ToString()
    {
        return _object.ToString();
    }

    int _index = -1;

    public IEnumerator GetEnumerator()
    {
        _index = -1;
        return this;
    }

    public object Current
    {
        get 
        {
            if (!(_object is JArray)) return null;
            object obj = (_object as JArray)[_index];
            if (obj is JValue) return ((JValue)obj).ToString();
            return obj;
        }
    }

    public bool MoveNext()
    {
        if (!(_object is JArray)) return false;
        _index++;
        return _index <(_object as JArray).Count;
    }

    public void Reset()
    {
        throw new NotImplementedException();
    }
}

- L.B

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非常好。那么如何覆盖ToString并将子对象作为JSON字符串返回，就像Console.WriteLine(json.glossary.GlossDiv.GlossList)一样？ - L.B