我创建了一个简单的pty设置,但是我不确定在创建后如何向主或从侧写入内容。我也不确定我的设置是否正确,因为在检查时,pty的子进程的Stdin、Stdout和Stderr都为None,而不是设置为从文件描述符。是否有人能够澄清这是否正确,并且如果不正确,请问有任何建议如何解决?
use libc::{self};
use nix::pty::openpty;
use std::os::unix::io::FromRawFd;
use std::process::{Child, Command, Stdio};
#[derive(Debug)]
pub struct Pty {
process: Child,
fd: i32,
}
fn create_pty(process: &str) -> Pty {
let ends = openpty(None, None).expect("openpty failed");
let master = ends.master;
let slave = ends.slave;
let mut builder = Command::new(process);
builder.stdin(unsafe { Stdio::from_raw_fd(slave) });
builder.stdout(unsafe { Stdio::from_raw_fd(slave) });
builder.stderr(unsafe { Stdio::from_raw_fd(slave) });
match builder.spawn() {
Ok(process) => {
let pty = Pty {
process,
fd: master,
};
pty
}
Err(e) => {
panic!("Failed to create pty: {}", e);
}
}
}
fn main() {
let shell = "/bin/bash";
let pty = create_pty(shell);
println!("{:?}", pty);
println!("{}", pty.process.id());
}
std::process::Child
类型不理解我传递到.stdin()等方法中的原始文件处理程序。鉴于这种情况,我是否最好从slave fd创建一个文件并使用它来操作? - EthalotChild
并不知道主进程。 - mcarton